Given the following half-reactions Mn2+(aq) + €2- -› Mn(s); E°= - 1.18 V Cu2+(ac) + €2- -Cu(s): E° = 0.34V Cr-0-2-(aq) + 14H*(aq) + €6- - 2Cp+ (aq) + 7H20(1); E° = 1.33V select the best reducing agent.
Given the following half-reactions Mn2+(aq) + €2- -› Mn(s); E°= - 1.18 V Cu2+(ac) + €2- -Cu(s): E° = 0.34V Cr-0-2-(aq) + 14H*(aq) + €6- - 2Cp+ (aq) + 7H20(1); E° = 1.33V select the best reducing agent.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.104QE
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Given the following half-reactions
Mn2+(aq) + €2- -› Mn(s);
E°= - 1.18 V
Cu2+(ac) + €2- -Cu(s):
E° = 0.34V
Cr-0-2-(aq) + 14H*(aq) + €6-
- 2Cp+ (aq) + 7H20(1); E° = 1.33V
select the best reducing agent.
Transcribed Image Text:Dadas las siguientes semireacciones
Mn2*(ac) + 2e -→ Mn(s) ;
E° = - 1.18 V
Cu2*(ac) + 2e- -Cu(s);
E° = 0.34 V
Cr20,2-(ac) + 14H*(ac) + 6e- → 2Cr3*(ac) + 7H2O(1); E° = 1.33 V
seleccione el mejor agente reductor.
Seleccione la respuesta correcta:
Mn
Cu
Cr3+
Cr2072-
Mn2+
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