Given two lists, create a dictionary whose elements are created as follows: The key will be equal to the first element in the first list, and corresponding value will be equal to the power of the first element in the second list (power value taken by second list), and so on. NOTE: Only dictionary comprehension solutions will be accepted. Örneğin: Sonuç {2: 4, 10: 1000, 20: 20, 12: 1, 15: 3375}

Given two lists, create a dictionary whose elements are created as follows: The key will be equal to the first element in the first list, and corresponding value will be equal to the power of the first element in the second list (power value taken by second list), and so on. NOTE: Only dictionary comprehension solutions will be accepted. Örneğin: Sonuç {2: 4, 10: 1000, 20: 20, 12: 1, 15: 3375}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

To create a dictionary, you just surround a sequence of value pairs of separated by: and the pair separated by commas, within curly braces. True or false?
import json, datetime, csvfrom pprint import pprint Question 3 - Using the cleaned list of lists from question 1, create a dictionary of dictionaries where each key in the outer dictionary is an author whose last name starts with the letter 'S'. - Each inner dictionary should contain the number of books that author has written as 'Number of Books' - It should contain the earliest book title for that author based on year with the key 'First Book' - Finally it should contain the latest book title for that author based on year with the key 'Last Book' - If an author has only one book put the same title in both places - Return the dictionary of dictionaries def author_history(cleaned_list): Args: cleaned_list (list) Returns: dictionary of dictionaries Output: {'SafranFoer,Jonathan': {'First Book': 'ExtremelyLoudandIncrediblyClose', 'Last Book': 'ExtremelyLoudandIncrediblyClose',…
Consider the code fragment provided above and the dictionary that would result when this code is executed. What would be the value in the dictionary associated with the key 42? This question is internally recognized as variant 245. Q9) 1 2 3 4 5 6 7 8 none of the above
Given hash_function( ) defined in the default template, complete the main function that does the following tasks: Create a list called hash_list that contains the five hashing algorithm names described above. Read from the user a password to hash. Declare a salt variable and initialize the variable to the hex representation of 4458585599393. Hint: Use function hex(). Use a for loop to iterate over the hash_list and call the hash_function() with the hashing algorithm names in the list. Store the returned value of hash_function() in a variable and output the algorithm name used and the hashed password. Note: Output a new line after each hashed password is printed. If the input is: secretPass the output is: Testing hash algorithm: md5 Hashed Password = bd19f99253c948637d64a4acbd524047:0x40e18692da1 Testing hash algorithm: sha1…
Given a dictionary where you have names of students as keys and their 3 exam grades as values, write a segment of code that calculates the average of every student and puts it in a list named averages. Then calculates the average of the class by averaging the results in the list averages. Run your code with the given dictionary studentExamGrades ## write your code in this cellstudentExamGrades = {"Alex":[90,75,60], "Sue":[100,88,95], "Matt":[66,80,75], "Raj":[55, 90, 70], "Sadie":[70, 89, 90]} #this is the given dictionary
You are given a list of courses that are currently available in BRACU that looks like the following: courses = ['CSE110','CSE111','MAT620','CS520','EEE361','CSE650','MAT5100','CSEE21','MAT3210']. All course code will have 3 digits with the department name of 3 letters. Any course code not following this rule is Invalid. Write a python program that creates a dictionary from the above list where the keys will be each department name (CSE,EEE,MAT for the above example) or Invalid. Departments will contain a list of valid courses for that department. Sample Input - No need to take input ['CSE110','CSE111','MAT620','CS520','EEE361','CSE650','MAT5100','CSEE21','MAT3210'] Sample Output : (You just need to print the resultatnt dictionary. No need to follow the format.) { 'CSE': ['CSE110','CSE111','CSE650'], 'EEE': ['EEE361'], 'MAT': ['MAT620'], 'Invalid': ['CS520','CSEE21','MAT5100','MAT3210'] }
In a dictionary, each element has two parts: a(n) _________ and a(n) _________.a. index, valueb. value, indexc. key, valued. integers, value
Assume a dictionary with some values: students = { 'CCU101': ['Anna', 88.5, 98.5, 78, 85, 92.5], ' CCU102': ['Alex', 98,91,90,92,88], 'CCU103': ['Bob', 99.5, 98.5, 96, 96, 89.5], } To access, a specific row, you would use students[key][column_number]. students['CCU101'][0] would print 'Anna' students['CCU101'][1] would print 88.5 and so on.. Write a program that defines a function that takes a dict as an argument, adds the scores of each student, calculate average for each student, and display them. Define a function display_average(students) that takes in a dictionary as an argument. Display the original dictionary. Calculate and display the average of each student. You do not need to ask user for input. You can use your own dictionary with at-least 5 rows.
1. Write a function invert_dict to reverse a dictionary, for example: >>> eng2sp = {'one': 'uno', 'two': 'dos', 'three': 'tres'} >>> sp2eng = invert_dict(eng2sp) >>> sp2eng {'uno':'one', 'dos':'two', 'tres':'three'} 2. Write a function print_dict to print all the key-values in a dictionary, for example: >>> d2 {'a': 'one', 'b': 'two', 'c': 'Three'} >>> print_dict(d2) a:one b:two c:Three
swift WAP for a dictionary is given print all values with key , then add one more entry .now print new dictionary and then change a value using key then again print new dictionary
Which of the following statements regarding linked lists and arrays is correct? Group of answer choices: a. A dynamically resizable array makes insertions at the beginning of an array very efficient. b. Using a doubly linked list is more efficient than an array when accessing the ith element of a structure. c. A dynamically resizable array is another name for a linked list. d. Any type of list tends to be better than an array when there are a set number of maximum items known beforehand. e. If many deletions at any place in the structure were common, a linked list implementation would likely be preferable to an array
Given a list mylist construct a dictionary mydict, the key is the index of an element in my list and its value will be the element value of mylist. for example the index of "a" is "0" . therefore the pair ( 0,"a" )will be in mydict .it means mydict = { 0:'a' ,1:'cybersecurity ', 2 : 'newyork'......} Do this in coding but not manually. given an empty dictionary mydict ={} write a python code to construct mydict for any given list. Hint : Your Code begins with mydict={}for val in mylist: