Given two strings S, and S2, using dynamic programming to calculate the Longest Common Sequence (based on iteration and recursion with memory). 0, if i=0 orj=0 ift.j>0 and S₁, = LCS[i-1][/-1]+1, LCS[.]= where i and i represent the indices of the characters of S, and Sz, and LCS[ A represents the length of the longest strands. (max{LCS[i,j-1], LCS[-1./1). if I.)>0 and S₁, S₂1 S21

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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calculate the Longest Common Sequence (based on iteration and recursion
Given two strings S, and S2, using dynamic programming to
with memory).
0,
LCS[i,j] =
LCS[i-1][-1]+1,
(max[LCS[i,j-1]. LCS[(-1./1).
if 1.)>0 and S₁, S₂j
where i and i represent the indices of the characters of Si and S2, and LCS[i, j]
represents the length of the longest strands.
#include <iostream>
#define
n
#define
m
20
30
if i=0 or j = 0
if tj>0 and S₁₁ =
using namespace std;
int LCS iteration (string s1, string sd
(
S21
Transcribed Image Text:calculate the Longest Common Sequence (based on iteration and recursion Given two strings S, and S2, using dynamic programming to with memory). 0, LCS[i,j] = LCS[i-1][-1]+1, (max[LCS[i,j-1]. LCS[(-1./1). if 1.)>0 and S₁, S₂j where i and i represent the indices of the characters of Si and S2, and LCS[i, j] represents the length of the longest strands. #include <iostream> #define n #define m 20 30 if i=0 or j = 0 if tj>0 and S₁₁ = using namespace std; int LCS iteration (string s1, string sd ( S21
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