Question
Asked Oct 4, 2019

Given two vectors A⃗ = 4.20 i^+ 7.60 j^ and B⃗ = 5.70 i^− 2.40 j^ , find the scalar product of the two vectors A⃗  and B⃗ .

 

Find the angle between these two vectors.

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Expert Answer

Step 1

The scaler product of unit vectors is:

jj1
kk =1
j.k 0
ki=0
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jj1 kk =1 j.k 0 ki=0

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Step 2

The scalar product of the two vectors is:

AB(4,20i+ 7.60i) (5.70i-2.40j)
AB 4.20i 5.70+7.60j-5.70î - 4.201-2.40j-7.60j-2.40j
AB 23.940-0-18.24
A B 5.7
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AB(4,20i+ 7.60i) (5.70i-2.40j) AB 4.20i 5.70+7.60j-5.70î - 4.201-2.40j-7.60j-2.40j AB 23.940-0-18.24 A B 5.7

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Step 3

The formula for the angle be...

AB
0 cos
| 4 B
5.7
= cos
(4.20+ 7.60 (/5.70 +2
V5.7022.402
83.91°
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AB 0 cos | 4 B 5.7 = cos (4.20+ 7.60 (/5.70 +2 V5.7022.402 83.91°

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Tagged in

Science

Physics

Vectors and Scalars

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