QUESTION 4Given:VDD = 28 VR1 =19 kohmsR2 = 3 kohmsRD = 581 ohmsRS = 0 kohmsRL = 10 kohmsID(on) = 16 mA at VGS(on) = 5 VVGS(th) = 3 Vgm = 25 mSSolve: Answers should be expressed using 2 decimal places QUESTION 4Given:• VDD = 28 VR1 =19 kohmsR2=3 kohmsRp= 581 ahmsRg =0 kohmsRL = 10 kohms• Dion) = 16 ma at VGsjon) = 5VVasin = 3V• m 26 ms Solve: Answars should be expressed using 2 decimal placesa. k (transter constant) =b. p=d. Vsa. VssV1. Vpskohms9. Rnta =h. Voltage gain, A =>

Note: We are authorized to answer three subparts at a time, since you have not mentioned which part…

Answered: Given • VDD = 2V • Rs19 kohms R=3 kohms…

Engineering

Electrical Engineering

Given • VDD = 2V • Rs19 kohms R=3 kohms Ro= set ahms Rs=0 kohms R10 kohms bjon) 16 mà a VosianV

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 3RQ: 3. What is the impedance of the circuit in Question 2?

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

QUESTION 4

Given:

VDD = 28 V
R₁ =19 kohms
R₂ = 3 kohms
R_D = 581 ohms
R_S = 0 kohms
R_L = 10 kohms
I_D(on) = 16 mA at V_GS(on) = 5 V
V_GS(th) = 3 V
g_m = 25 mS

Solve: Answers should be expressed using 2 decimal places

QUESTION 4
Given:
• VDD = 28 V
R1 =19 kohms
R2=3 kohms
Rp= 581 ahms
Rg =0 kohms
RL = 10 kohms
• Dion) = 16 ma at VGsjon) = 5V
Vasin = 3V
• m 26 ms

Solve: Answars should be expressed using 2 decimal places
a. k (transter constant) =
b. p=
d. Vs
a. Vss
V
1. Vps
kohms
9. Rnta =
h. Voltage gain, A =
>

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