Grams of KHP 0.313 0.3179 0.3159 Moles of KHP (Equivalent to Mols NaOH) Millimeter NaOH used to titrate Calculated Molarity of NaOH 0.001532586 0.01574 0.001556578 0.01712 0.001546785 0.01556 Average Molarity

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter13: Titrations In Analytical Chemistry
Section: Chapter Questions
Problem 13.18QAP
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I need help calculating the three trials of molarity of NaOH and find the average molarity.
Grams of KHP
0.313
0.3179
0.3159
Moles of KHP (Equivalent to Mols NaOH)
0.001532586
0.001556578
0.001546785
Millimeter NaOH used to titrate Calculated Molarity of NaOH
0.01574
0.01712
0.01556
Average Molarity
Transcribed Image Text:Grams of KHP 0.313 0.3179 0.3159 Moles of KHP (Equivalent to Mols NaOH) 0.001532586 0.001556578 0.001546785 Millimeter NaOH used to titrate Calculated Molarity of NaOH 0.01574 0.01712 0.01556 Average Molarity
Expert Solution
Step 1

 

 The chemical reaction between KHP and NaOH takes place in the following way -                                    KHP + NaOH  NaKP + H2OFrom the above balanced molecular reaction, the mole ratio of KHP and NaOH is -                                           KHP : NaOH                                              1    :    1                        From stoichiometric coefficientSo, number of moles of KHP = Number of moles of NaOH Millimeter is the unit of length while milliliter is the unit of volume .So, it should be Milliliter NaOHused to titrate, not Millimeter NaOH used to titrate.

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