Graph and locate the foci: y2 - 4x2 = 4. What are the equations of the asymptotes?

Q: (x – 2)² (y – 3)² Graph: = 1. Where are the foci located? What are the 16 equations of the…

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Q: Find the asymptotes of the hyperbola. y^2-x^2=4

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Q: Put the equation in standard form then sketch a graph indicating the foci, and asymptotes: y? - 4x2…

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Q: Write an equation for the hyperbola that has foci at (0,1113) and (0,- 113), and asymptotes y = +…

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Q: Find an equation of the parabola whose graph is shown. y Directrix X = 4

A: Equation of directrix is  X=a

Q: Graph the hyperbola, y2 - 4y - 4x2 + 8x - 4 = 0. Locate the foci and find the equations of the…

A: Given that : The equation of the hyperbola is y 2 - 4y - 4 x 2 + 8x - 4 = 0.

Q: Find an equation of the parabola whose graph is shown. y Focus

A: In this problem , parabola symmetric about y - axis . Vertex form of parabola if symmetric about y -…

Q: y² For the hyperbola = 1, the asymptotes are 81 16 and

A: we have to fill in the blanks: For the hyperbola y216-x281=1, the assymptotes are ________ and…

Q: Find the​ center, transverse​ axis, vertices,​ foci, and asymptotes. Graph the following equation.…

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Q: The equation of the asymptote having a positive slope to the shown hyperbola is

A: The given graph of hyperbola,

Q: y2 1. What are the 36 Graph and locate the foci: equations of the asymptotes?

A: Given: x236-y29=1 We know that foci of given equation of hyperbola is given by foci≡±ae,0…

Q: Graph: 4x2 + 36y2 + 40x - 288y + 532 = 0. Where are the foci located?

A: On simplification, we get

Q: Find an equation of the parabola with vertex , 34 and directrix =y2 .

A: It is given that the vertex of the parabola is (3,4), where h = 3 and k = 4 and the directrix is y =…

Q: use the method of completeing the sqaure to find the vertex of the parabola whose equation is…

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Q: Write an equation for the hyperbola that has foci at (0, 65) and (0, - 65), and asymptotes y = ±8x.

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Q: Q1) Find an equation of the following parabola and sketch it where Vertex: (3,2) and Focus:(1,2)

A: Given the vertex 3,2 and the focus 1,2 of a parabola. We need to find the equation of the parabola…

Q: y = 3x? + 6x – 5

A: The given parabola is: y=3x2+6x-5...(1)

Q: 3. Put the equation in standard form then sketch a graph indicating the foci, and asymptotes: y? –…

A: Given - y2 - 16x2 + 64x - 208 = 0 To find - Put the given equation in standard form. Sketch the…

Q: What is the focus of the following parabola? (y + 5)² = -12 (x - 2)

A: Given,  (y+5)2=-12(x-2)

Q: Sketch the graph of 2x2 + 9y2 = 18, and find the foci.

A: We  have to find the foci of the given equation   we have the given function as 2x2 + 9y2 = 18 we…

Q: FInd the center,transverse axis,vertices,foci,and asymptotes.Graph each equation.

A: 2y2-x2+2x+8y+3=0 On simplification, we get…

Q: Find the equation of the Hyperbola with asymptotes y=±2x and a vertex at (0, 10)

A: Given, The asymptotes of the hyperbola is  y=2x  and   y=-2x  and vertex at 0, 10 We have to find…

Q: Graph: x2 + 4y2 + 10x + 24y + 45 = 0. Where are the foci located?

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Q: What are the slopes of the asymptotes for the hyperbola whose equation is 4x2-9y? = 36? %3D

A: Here, the given equation of the hyperbola is: 4x2-9y2=36 In standard from it can be written as:…

Q: Given the equation x2 − 22x + 2y2 + 57 = 0 find the foci, vertices, directrix, axis, and asymptotes,…

A: Given equation of ellipse: x2-22x+2y2+57=0 The above equation can be rewritten as: x2-22x+2y2=-57…

Q: Graph the parabola by finding the vertex, directrix, focus, and Latus Rectum. 4. y2-16y-12x +40 = 0…

A: we have to find the following

Q: FInd the center,transverse axis,vertices,foci,and asymptotes.Graph each equation

A: Given equation is y216-x24=1. To find the center, transverse axis, vertices, foci and asymptotes.…

Q: find the intercepts and the equations for the asymptotes.4x2 - 9y2 = 16

A: GIVEN 4X2-9Y2=16 We need to find the intercepts and the equation for the  asymptotes .

Q: Graph the parabola y2 - 2x - 2y - 5 = 0. Give the location of the focus and the directrix.

A: We have to graph the parabola and we have to give the location of the focus and the directrix where…

Q: Find the length of the diameter of the ellipse 3x2+y2 +2x-6y=0. Which has a slope of 2.

A: Ellipse

Q: Betty was asked to write the equation of the hyperbola with asymptotes y = +x and x-intercepts…

A: Definition used -               Equations of the asymptotes of the hyperbola are-…

Q: A hedge is to be constructed in the shape of a hyperbola near a fountain at the center of the yard.…

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Q: Find an equation of the parabola with focus (-8,5) and directnx X = 4,

A: Parabola is the locus of a point, which moves so that its distance from a point called focus and a…

Q: Graph: 4x2 - 24x - 9y2 - 90y - 153 = 0. Where are the foci located? What are the equations of the…

A: Given equations is 4x2-24x-9y2-90y-153=0. Given equation can be written as:…

Q: Determine the foci and the lequations of the asymptotes, and sSket ch the graph of the parabola.

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Q: Find the equation of the hyperbola whose asymptotes are y = 2x and y=-2x which passes thru (5/2, 3).

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Q: y A -3 2 5

A: Vertical asymptotes are those lines which the curve never intersects but runs parallel to it upto ∞.

Q: Write an equation for the hyperbola that has foci at (0, v65) and (0, - v65), and asymptotes y =…

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Q: find the equations of the asymptotes for each hyperbola. y2 - 16x2 = 36

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Q: Graph: 4x2 - 24x - 25y2 + 250y - 489 = 0. Where are the foci located? Whatare the equations of the…

A: Given equation, 4x2 - 24x - 25y2 + 250y - 489 = 0 we have to tell where are the foci located and…

Q: Find an equation for the hyperbola that satisfies the given conditions. Foci: (0, +9), asymptotes: =…

A: Given foci (0,±9) , asymptotes y=±12x let’s find an equation of hyperbola

Q: Graph the hyperbola y2 - 4y - 4x2 + 8x - 4 = 0. Locate the foci and find the equations of the…

A: To graph the given hyperbola                y2 - 4y - 4x2 + 8x - 4 = 0 To locate the foci and find…

Q: Graph: (x - 1)2/4 + (y + 2)2/9 = 1. Where are the foci located?

A: Consider the given equation, x-124+y+229=1 here the objective is to graph the ellipse and locate the…