Please answer question and just send me the paper solutions asap dont type the answer question 3abcd only And use the formula that is given dont use any other formula and use 9.81 for acceleration not 9.8 if required please solve it faster asap and dont give wrong answer Equations and ConstantsF = µPmsinAsinBsincFnet = maa? = b2 + c? -2bccosAab.CV2 = V1 + aAtAdAd = v;At + ½aAťAd = v2At - ½aAťVavAd = %(v1 + v2)At(vz) = (v1} + 2aAdv2a. =g = 9.814n rf2T2W FAdW= ΔΕPE = mgAy1KE =mv22.F = kxElastic Energykx2P= mvFAt = ApGMmmearth = 5.972 x 1024kgmmoon = 7.348 x 1022kgFgNm2G = 6.67x10-11kg2re = 6378 kmTmoon = 1737 mkq,92F. =mproton = 1.67 x 10-27kgmelectron = 9.11 x 10-31kgNm2k = 9.00x109C2lelectron/proton+1.60x10-19CFmagnetic = qvBsin® gun, Caiculatc no W Tai uiT II IS away HO uc guuT (0.04A1TOʻ III)3. A ball is fired from a cannon inclined at 36.9° above the horizontal. The speed with which itleaves the barrel is 200 m/s and the mouth of the cannon is 2.00 m above ground level.Assume level ground.What are the horizontal and vertical components of the initial velocity of thecannon ball?Determine the velocity of the cannon ball at t = 6.0 s.What is the ball's velocity when it reaches its maximum height?How far down range (from the cannon mouth) does the ball land?(b)(d)

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gun, Caiculate no W Tai uiC II IS away nomT uc guu (0.04A1TO I) 3. A ball is fired from a cannon inclined at 36.9° above the horizontal. The speed with which it leaves the barrel is 200 m/s and the mouth of the cannon is 2.00 m above ground level. Assume level ground. What are the horizontal and vertical components of the initial velocity of the cannon ball? Determine the velocity of the cannon ball at t = 6.0 s. What is the ball's velocity when it reaches its maximum height? How far down range (from the cannon mouth) does the ball land? (b) (d)

gun, Caiculate no W Tai uiC II IS away nomT uc guu (0.04A1TO I) 3. A ball is fired from a cannon inclined at 36.9° above the horizontal. The speed with which it leaves the barrel is 200 m/s and the mouth of the cannon is 2.00 m above ground level. Assume level ground. What are the horizontal and vertical components of the initial velocity of the cannon ball? Determine the velocity of the cannon ball at t = 6.0 s. What is the ball's velocity when it reaches its maximum height? How far down range (from the cannon mouth) does the ball land? (b) (d)

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 76P: A small plane flies at 200 km/h in still air. If the wind blows directly out of the west at 50 km/h,...

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