Question
Asked Oct 30, 2019
Gven: 10mL of Hd
Dotll=
mass of NaOH2.013a
MHC-
1.0 OM
M Naot-1.0OM
NaOt(s)+HCI CaqNaulaa+H2O)
Atrin J/mol
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Gven: 10mL of Hd Dotll= mass of NaOH2.013a MHC- 1.0 OM M Naot-1.0OM NaOt(s)+HCI CaqNaulaa+H2O) Atrin J/mol

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Expert Answer

Step 1

The number of moles of a species is calculated by expression (1), in which, n is the number of moles, m is the mass, and M is the molar mass of the species.

The molarity of a solution is the number of moles of solute present in one-liter solution as stated in equation (2), where, M is the molarity of solution, n is the number of moles, and V is the volume of solution in liters.

The enthalpy change of a reaction (ΔHrxn) is related to its specific heat in accordance with expression (3), in which, m is the mass of the metal, s is the specific heat, n is the number of moles of the limiting reactant, and ΔT is the change in temperature.

т
(1)
п
М
п
(2)
М-
V (in L)
msAT
ΔΗ,
(3)
n
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т (1) п М п (2) М- V (in L) msAT ΔΗ, (3) n

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Step 2

The number of moles of NaOH in the given reaction is calculated using equation (1),

2.073 g
п-
40.0 g/mo
0.0518 mol
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2.073 g п- 40.0 g/mo 0.0518 mol

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Step 3

The conversion factor for mL and L units is,

1 mL = 10-3 L

Hence, 100 mL is equal to 0.100 L.

The...

п
1.00 mol/L
0.100 L
0.100 mol
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п 1.00 mol/L 0.100 L 0.100 mol

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