х — 4у — 22 y + 2z - 2x + 7y + (k² – 2)z 2 Use the system of equations 2 for problems 9 and 10. k – 4 9. The value(s) of k such that the system has a unique solution is (are): (a) k +2 (b) k = -1,2 (c) k # ±2 (d) k + -2 (e) None of the above. 10. The value(s) of k such that the system has no solution is (are): (а) k %3 2, -3 (b) k = 0 (c) k = 2 (d) k = -2 (e) None of the above.
х — 4у — 22 y + 2z - 2x + 7y + (k² – 2)z 2 Use the system of equations 2 for problems 9 and 10. k – 4 9. The value(s) of k such that the system has a unique solution is (are): (a) k +2 (b) k = -1,2 (c) k # ±2 (d) k + -2 (e) None of the above. 10. The value(s) of k such that the system has no solution is (are): (а) k %3 2, -3 (b) k = 0 (c) k = 2 (d) k = -2 (e) None of the above.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:х — 4у — 22
y + 2z
- 2x + 7y + (k² – 2)z
2
-
Use the system of equations
2
for problems 9 and 10.
k – 4
9. The value(s) of k such that the system has a unique solution is (are):
(a) k + 2
(b) k = -1,2
(c) k # ±2
(d) k + –2
(e) None of the above.
10. The value(s) of k such that the system has no solution is (are):
(а) k %3D 2, —3
(b) k = 0
(c) k = 2
(d) k = -2
(e) None of the above.
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