As shown in the figure below, a box of mass m= 69.0 kg (initially at rest) is pushed a distance d = 89.0 m across a roughwarehouse floor by an applied force of FA= 206 N directed at an angle of 30.0° below the horizontal. The coefficient ofkinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give youranswer to the nearest multiple of 10.)(a) work done by the applied forceWA"30(b) work done by the force of gravityWg=(c) work done by the normal forceWN=(d) work done by the force of frictionW, =(e) Calculate the net work on the box by finding the sum of all the works done by each individual force.3W NetW Netrough surface(f) Now find the net work by first finding the net force on the box, then finding the work done by this net force.J=

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H As shown in the figure below, a box of mass m = 69.0 kg (initially at rest) is pushed a distance d = 89.0 m across a rough warehouse floor by an applied force of FA 206 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) √30 (a) work done by the applied force WA= (b) work done by the force of gravity W₂ = (c) work done by the normal force WN= (d) work done by the force of friction W, = rough surface (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. W Net (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. W, W Net J

H As shown in the figure below, a box of mass m = 69.0 kg (initially at rest) is pushed a distance d = 89.0 m across a rough warehouse floor by an applied force of FA 206 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) √30 (a) work done by the applied force WA= (b) work done by the force of gravity W₂ = (c) work done by the normal force WN= (d) work done by the force of friction W, = rough surface (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. W Net (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. W, W Net J

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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