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H=? Eq.1 H, + O2 = H,0 Eq.2 N,O, + H,0 = HNO, Eq.3 N, + H= -167 J H= 15 J O2 + H, = HNO, H=122 J

H=? Eq.1 H, + O2 = H,0 Eq.2 N,O, + H,0 = HNO, Eq.3 N, + H= -167 J H= 15 J O2 + H, = HNO, H=122 J

Principles of Instrumental Analysis
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter6: An Introduction To Spectrometric Methods
Section: Chapter Questions
Problem 6.19QAP
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Ng + Og+ → N,0; H=? H= -167 J Eq.1 H2 + 02 = H,0 Eq.2 NO; + H0 = HNO, Eq.3 N2 + O2 H= 15 J + H2 = HNO, H=122 J 2.JEq.1 CH,OH + O, = C0, + H,0 H= 300.9 Eq.2 C + 0, = C02 + O2 H= -86.77 J Eq.3_ H, + 0, = H,0 H=98.8 J Final Equation: ? Final System Enthalpy: ?
Transcribed Image Text:Ng + Og+ → N,0; H=? H= -167 J Eq.1 H2 + 02 = H,0 Eq.2 NO; + H0 = HNO, Eq.3 N2 + O2 H= 15 J + H2 = HNO, H=122 J 2.JEq.1 CH,OH + O, = C0, + H,0 H= 300.9 Eq.2 C + 0, = C02 + O2 H= -86.77 J Eq.3_ H, + 0, = H,0 H=98.8 J Final Equation: ? Final System Enthalpy: ?
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