I don't think I did this right. h) Find Moles of Reaction (Mg is the limiting reagent, so calc how many moles of Mgqrxn Ou 453reacted from grams of Mg)Mg Do 23 25g * Imol mg24031g mgi) AH = qrxn /molesen-06453 k0.0095 64 muligSun Ve NG-NAVNE103810 polecela da pra caster'sCFIGHT CAN HOS(0) NOSo,TOMISSIS= 0.009539 mabl Mgmoles: 0.009564 mol MgpallpAHxn2-4164 kj/mol= -47.36 kJ/moldal secondCASTEMT CASHMusContentCAJHOST) estiscontMY OH 7 ) Mtad po tom 21.06's ton/10HAR-cscborg HAS ACOROEST139 3) Calculate qn and AH for the 1 M HC1/Mg Ribbon Rxn.The amount of energy the reaction gives off (-qrnx) is given to the solution in the calorimeterand the calorimeter itself. This means that -qrxn is equal to the amount of energy the solutionabsorbed (qso) and the energy the calorimeter absorbs (qeal) Mathematically, the equation thatdescribes this is:-qrxn (qsol +qcal) orqrxn-[(msol X Csol X AT) + (Ccal X AT)]Note that Tmax is the final temperature for all species when calculating the AT. To convertvolume of the solution to g of solution use the following: the density of 1 M HCl is 1.01 g/mL.The specific heat of the solution is 4.04 J/g °C.Calculate the following:qrxn=-(qsol+qcal)a) Volume of HCl(from data)VHCI 100..b) Find mass of the solution using the mL of HCl and the density given above100.0 mL x 1001 g/mL = 10lg gc) Find the initial temp of the HCI (from data)d) Find the maximum reaction temp from dataHe) Find AT(AT=Tmax-Tinitial)33.2°C -20.2°C =g) Convert qrn to kJlks-45351000)msol: 10.09*H0all Joe.deTinital: 20-2°CTmax: 33.22f) Find qrxn2009 (9rxn=- [(msol X Csol X AT) + (Ccal X AT)]) where Csol is given above, and Ccal iscalculated in part 1.ΔΤ: [3.00 c°-[(1010gx 4:04 J/g °C x 13.006) + (23602 j/2 x 13.00) = -452.78-153.92 +-299.269rxn-4531(should be negative)0.453k138

The heat released or absorbed (q) when the temperature of any substance is raised is calculated as:…

h) Find Moles of Reaction (Mg is the limiting reagent, so calc how many moles of Mg reacted from grams of Mg) 9rxn O. 453 ng 0.23 25g * /mol mg 2.168.3- 3 i) AH = qrxn /moles 240319 mg 0.0095 39 mb) Mga y counts A -06453 kJ A5111 spl) + past moles: 0.009564 mol Mg 4 AHrxn2-4104 kj/mol =-47.36 kj/mol 1.76

h) Find Moles of Reaction (Mg is the limiting reagent, so calc how many moles of Mg reacted from grams of Mg) 9rxn O. 453 ng 0.23 25g * /mol mg 2.168.3- 3 i) AH = qrxn /moles 240319 mg 0.0095 39 mb) Mga y counts A -06453 kJ A5111 spl) + past moles: 0.009564 mol Mg 4 AHrxn2-4104 kj/mol =-47.36 kj/mol 1.76

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter12: Thermodynamic Processes And Thermochemistry

Section: Chapter Questions

Problem 42P

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