H.W. 13: Switch S, in Fig.1 is closed at t = 0, and switch S, is closed at t = 2s. Calculate i(t) for all t. Find i(1) and i(3). Answer: t- 2 (0, i(t) ={2(1 - e-t), (3.6 - 1.6e-5(t-2). t<0 0 2 20 2 i(f) t=0 i(1) = 1.9997A, i(3) = 3. 589A. 6A 152 SH

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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H.W. 13: Switch S, in Fig.1 is closed at t = 0, and switch S, is closed at t = 2s. Calculate i(t) for all t. Find i(1) and i(3).
Answer:
t=2
0,
t<0
i(t) = {2(1 - e-9t),
(3.6 1.6e-5(t-2),
0 <t< 2
10Ω
ww ww
t>2
20 2
t=0
i(1) = 1.9997A, i(3) = 3.589A.
6A
SH
15Q
Fig.1
Transcribed Image Text:H.W. 13: Switch S, in Fig.1 is closed at t = 0, and switch S, is closed at t = 2s. Calculate i(t) for all t. Find i(1) and i(3). Answer: t=2 0, t<0 i(t) = {2(1 - e-9t), (3.6 1.6e-5(t-2), 0 <t< 2 10Ω ww ww t>2 20 2 t=0 i(1) = 1.9997A, i(3) = 3.589A. 6A SH 15Q Fig.1
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