H.W. No.1 2nd semesterQ-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinalslope=S= 1:1175.5, n=0.0218.Find;Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R,Flow velocity=V, and Q= Flow rate or discharge,TV= 4y2=VH or Z=104 =H or ZAnswers are given below, solve and check. Sendyour detail solution with drawing.Top width=T= 22.1950mP=22.928m , Hydraulic radius=R= 1.3684m , Flow velocity=V= 0.5215m/sec,Q= Flow or discharge= 16.361m³/sec.Flow area =A = 32.374m², Wetted perimeter=Solve and send your detail solutionQ-2. If discharge Q=6.9134 m³/sec, left side slope 5:3(H:V), Left side slope=6:3, bed slope 2:8250, flow depth=y=1.8m, Bed width=b=10.55m.Find.Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, andFlow velocity=V. Draw and put all dimensions.

Name: H.W. No.1 2nd semesterQ-1: Given ; b= base width =14.5m, Flow depth=1
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Description: H.W. No.1 2nd semesterQ-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinalslope=S= 1:1175.5, n=0.0218.Find;Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R,Flow velocity=V, and Q= Flow rate or discharge,TV= 4y

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H.W. No.1 2nd semester Q-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinal slope=S= 1:1175.5, n=0.0218. Find; Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, Flow velocity=V, and Q= Flow rate or discharge,

H.W. No.1 2nd semester Q-1: Given ; b= base width =14.5m, Flow depth=1.71m, channel longitudinal slope=S= 1:1175.5, n=0.0218. Find; Top width=T, Flow area =A, Wetted perimeter= P, Hydraulic radius= R, Flow velocity=V, and Q= Flow rate or discharge,

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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