hat is the molecular formula of a compound containing 24.27 carbon, 4.07% hydrogen and 71.76% chlorine by a mass? The molar mass of the compound is 98.96 amu.

Q: A compound has an empirical formula of C3H¬NO and a molar mass of 146.22 g. What is its molecular…

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Q: A 125.6 mg sample of an organic compound containing only carbon, hydrogen, and nitrogen is combusted…

A: Answer The empirical formula is C3H8N The molecular formula is C6H16N2

Q: What is the molecular formula of a compound with an empirical formula of CH and a molar mass of 78.1…

A:

Q: What is the mass, in grams, of 9.55×1024 molecules9.55×1024 molecules of methanol (CH3OH)?

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Q: A. Molar mass of an Element = Atomic mass of the Element Molar mass of a Compound = Molecular mass…

A: Given: Molar mass of C = 12.01 g/mol Molar mass of O = 16.00 g/mol Molar mass of Pt = 195.08 g/mol…

Q: What is the molecular formula of a compound with the empirical formula CH2OCH2O and a formula mass…

A:

Q: 1. A certain compound is accidentally synthesized by a chemist in a laboratory set-up. He discovers…

A: Number of moles of any substance = mass of substance/molar mass of substance  Mol ratio for…

Q: Three elements, A, Q, and Z, have the molar masses indicated in the table below. Given a compound…

A: empirical formula has to be determined using the given data

Q: 1. a. What is the empirical formula of a compound with the following mass composi- tion: 40.92% C…

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Q: 5. Aspartame is an artificial sweetener that is 160 times sweeter than sucrose (table sugar) when…

A: Molecular formula is C14 H18 N2 O5  We need to find it's molar mass.  Amount of molecules in 10.0 g…

Q: A compound contains 24.3% C, 4.1% H, and 71.6% Cl by mass, and has a molar mass of 99 g/mol. What is…

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Q: When 3.232 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 11.10 grams…

A: Data given: Mass of sample = 3.232 g Mass of CO2 = 11.10 g Mass of H2O = 1.818 g Molar mass of the…

Q: A compound is composed of 54.50% O, 4.58% H and 40.92% C by mass. If the compound has a formula…

A: Empirical formula- It represents simplest whole number ratio of various atoms present in the…

Q: A sample of compound X is subjected to elemental analysis and the following percentages by weight…

A: Given   % C = 39.97 %  % H  =  6.73 %  % O  =  53.30  Empirical formula = ?

Q: The percentage composition of an organic compound CxHyOz is 40.00 % C, 6.73 % H and 53.27 % O. Its…

A: Lets suphose the compound has moler mass = 100g/mol So, there is 40g c , 6.73 g  and 53·27 g.40g…

Q: Calculate the molar mass (g/mol) of the compound. NaNO2

A: Calculate molar mass of NaNO2 ?

Q: What is the molecular formula of a compound

A: Given :- molar mass of compound  = 220 g/mol            Empirical formula = P2O3.  To find :…

Q: Gun powder reacts according to the following reaction: 10 KNO3 (s) + 8 C (s) +3 S (s) → 2 K2CO3 (s)…

A: We can solve this problem by using defination of mole  Mole is difine as ratio of mass of substance…

Q: What is the mass percent composition of oxygen in a compound having the empirical formula C20H34O4?

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Q: A 125.6 mg sample of an organic compound containing only carbon, hydrogen, and nitrogen is combusted…

A:

Q: A pure sample of an unknown molecule has a mass of 35.51 g and contains 0.2000 moles. What is the…

A: 177.55 g/mol

Q: What mass of XeCl4 contains 11.245 x 1022 molecules of XECI4? Molecular mass (g/mol) XeCl4: 273.09…

A: We determined mass of XeCl4 by using avogadro's number. NA = 6.022×1023 molecules per mole .

Q: Most fertilizers consist of nitrogen-containing compounds such as NH3, CO(NH2)2, NH4NO3, and…

A: The compounds which are used as fertilizers are given as NH3, CO(NH2)2, NH4NO3, and (NH4)2SO4.

Q: Ethylene glycol, the substance used in automobile antifreeze, is composed of 38.7% C, 9.7% H, and…

A: Let us assume we have 100 g of Ethylene glycol, then percentages become grams as follows –  mass of…

Q: A compound contains 39.0 % C, 6.72 % H and 53.4 % O by mass. a) What is its empirical formula? b)…

A: Given:  A compound contains 39.0 % C, 6.72 % H and 53.4 % O by mass which means that 100 g of a…

Q: What is the mass of 5.45 x 10 -3 mol of glucose C 6 H 12 O 6? O a. 981 g b.0.981 g O c. 0.158 g O…

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Q: 2.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have…

A: Empirical formula :- The formula which gives the simplest whole number ratio of atoms of various…

Q: Titanium tetrachloride, TiCl4 , is prepared by the reaction below.…

A: Given, Mass of TiO2 = 35g. Mass of Cl2 = 38g. Mass of C = 11g. The balanced reaction for the…

Q: A 3.06 mg sample of a compound containing carbon, hydrogen, and oxygen underwent combustion…

A: Empirical formula: Formula containing atoms in smallest possible integer ratio Molecular formula:…

Q: Chromium(III) oxide can be made from the reaction of sodium dichromate and ammonium chloride. What…

A: Given, mass of  sodium dichromate (Na2Cr2O7) = 108.7 g mass of ammonium chloride (NH4Cl) = 61.6 g…

Q: What is the mass in grams of 6.56 x 1022 molecules of lactic acid (C3H6O3), the compound responsible…

A: 1- First we need to calculate the moles of lactic acid :  Moles of lactic acid = [ number of…

Q: A compound having an approximate molar mass of 165-170g has the following percent composition by…

A: From percentage composition we can determine empirical and molecular formula. Empirical Formula =…

Q: Acrylonitrile (C3 H3N) is the starting material for many synthetic carpets and fabrics. It is…

A: First we have to determine the limiting reagent. Limiting reagent is that which consumed first or…

Q: A mixture of gases has the following composition by mass: O2 CO 16% (Xo, = 0.16 g O,/g total) 4.0%…

A: We have to find molar composition of gases

Q: A molecular compound contains carbon, hydrogen, and oxygen atoms in its formula. A chemical analysis…

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Q: An unknown hydrocarbon is subjected to elemental analysis. It is determined to be 85.6% carbon and…

A: Mass % of Carbon = 85.6% Mass % of Hydrogen = 14.4% Empirical formula =?

Q: What is the mass (g) of 0.826 moles of acetic acid? The molar mass of HC2H3O2 is 60.06 g/mol.    a.…

A: Given, Number of moles of acetic acid = 0.826 moles Molar mass of acetic acid = 60.06 g/mol Mass of…

Q: Air has an approximate composition by mass of 76.7% N 2 and 23.2% O 2 . How many Ib-moles of air are…

A: Given the composition of air is 76.7% N2 and 23.2% O2.  Fraction of N2 = 76.7/100 = 0.767 Fraction…

Q: What number of molecules (or formula units) are present in 4.70 g of each of the following…

A: We have to calculate number of molecules in 4.70g of each compounds.

Q: A compound has the empirical formula CH,O and a molar mass of approximately-180. g/mol. What is its…

A: Divide the molar mass of the compound by the empirical formula mass. The result should be a whole…

Q: 5. The empirical formula of a compound is CaH10. hat could its molecular formula be 86 6. A compound…

A: SOLUTION [5.] : Empirical formula of a compound = C4H10O So, molecular formula of a compound will be…

Q: What is the chemical formula of a compound with an empirical formula of CH2O and a molar mass of…

A:

Q: What is the molecular formula of a compound which has an empirical formula of CH2 and a molar mass…

A: The empirical formula is CH2​. Therefore, the empirical weight = 14.Given, the molecular weight…

Q: Elemental analysis of a sample containing only B and H shows that it contains 479.4 g of boron…

A:

Q: Cryolite (Na3AlF6) is used in the production of aluminum from its ores. It is made by the reaction 6…

A: First, calculate the moles of Al2O3 Moles = Mass/Molar mass = 287 g/(101.96gmol-1) = 2.815 moles

Q: Ethanol (C 2H 6O, molar mass 46.07 g/mol) is synthesized by reacting ethylene (C 2H 4, molar mass…

A: Given that:  molar mass of Ethanol = 46.07 g/mol molar mass of ethylene = 28.05 g/mol mass of…

Q: What number of molecules (or formula units) are present in 3.07 g of each of the following…

A: Given,  Mass of each compound = 3.07 g  Then,  Find number of molecules in = ?  a). NH3  b). N2H4…

Q: Determine the molecular formula of a sugar from its percent composition of 40.0% C, 6.67% H, 53.3%…

A: Given : Mass percent of C = 40.0 % Mass percent of H = 6.67 % Mass percent of O = 53.3 % And molar…

Q: When 1.915 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.474 grams…

A: The general equation for the combustion reaction of hydrocarbon, CxHy, in the presence of oxygen is:…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.