Q: 7. Chioroethane + CH;ONa a. Ethane • water H,50. . CH,CH;CCH, • LIAIH, 140°C ether 1n 2moles of…
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A: The IUPAC name of the molecule is explained as follows:
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A: The broad peak around 3500-3300 cm-1 is of O-H peak.
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Q: CH2 CH3 CH CH2 CH2 CH2 CH3 CH3 CH CH2 CH3 CH3 CH2 CH ČH3 CH, CH CH-CH-CH-С — СН-CH, ČH,
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Q: eagenser a CH;CH2C `OH CH3CH2C `OCH3 CH;CH2CH2OH OH CH;CH,Ċ-CH3 ČH3
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Q: Name each alkene. a. CH;-CH,-CH=CH-CH,-CH; b. CH,-CH-CH=CH-CH, CH3 CH; CH, c. CH,-CH-CH=C-CH-CH, CH3…
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Q: 4. Name the following compounds: a. CH,CH,CH,CH; CH, CH, M CH3 CH2 ČH2 CH3 b. CH-CH-C C-CH, CH, CH2…
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Q: a) CH3- CH2- CH2OH c) OH OH CH3 CH - CH2 CH3 b) CH3 - CH – CH3 d) CH3 - C- CH3 OH OH
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A: Give IUPAC name of the given--
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Q: HO 3. 4. CH,CH CH3 CH3 HO, 4-Chloro-3-ethylcyclohexan-1-ol CH, 6. CH,CCH,CH,CH,CI 5.
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Q: Write down the IUPAC name and structure of the followings (i) HOH,C-CH = CH - CH,OH (ii) H.C…
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Q: Which structure is different from the following? * HCH3 CH3 CH3 a) CH3 CH, CH, b) H H3C- CH3 CH3 H H…
A: Identify the different structure. 1 ,2 methyl are trans to each other. 1,4 methyl are trans to…
Q: e. H,CH,C(CH32CH2CH(F)CH(CH,CH3)CH3 1,3,3-trichloro-2-methyl-pentane…
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Q: 7. CH3(CH3)CH=CH2 3. CH3CH2CH2C(CH3)=C(CH3)CH2CH3 э. СНЗCH2CH(CHз)C-CH 10. CH3CH=CHCH2CH=CH2
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Q: Which is cyclobutene? CH2 CH2 CH CH2-CH || W CH2-CH CH CH2 CH2 CH Y I Z CH2 CH CH2 CH2- CH CH2- CH O…
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Q: Which of the following is (are) possible Newman projections for 2-methylpentane?
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Q: a) ? -CI ? b) с-он -CH2OH с) ? -C-H С-он d) ? CH3CH2CH2C-OH CH,CH,CH2C-ONa
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Q: CH,CH,ČCH;CH, + H , CH-C-H +CH,CH,OH → CH3O Na + CH3CH2C1→ H30 CH3CH CONH2 → CH,CH,CH,-C-CI +…
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Q: Which is a stronger base?
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Q: B. Give the IUPAC name of the following: 6 CH, CH,- CH CH, CH H,C CH CH,-CH, ÇH-CH, H,C-CH,-CH,- CH-…
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Q: CH3 d. H2C=CH -CEN H2C=CH-Ć=CH2 +
A: The question (d) involves a diene and a dienophile. It is an example of diels alder reaction. The…
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A: Organic compounds are the compounds which are mainly composed C and H atoms. The branch of chemistry…
Q: ollowing compound? CH3 CH,CH,CH, CH,-C-CH,–CH–CH, CH,CH,
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Q: CH, CH-CH-CH=CH-CH, Oa 2-methylpentene b) 4-methyl-2-pentene C02methyl-3,4-pentene…
A: All chemical compounds can be named with certain rules which are purposed by IUPAC. It purposed to…
Q: HX C=C HX -C-C- Alkene Alkyl halide H. H OH H,O C=C - C-C- Alkene Alcohol
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A: ->Electron donating groups are ortho -para directing when attached to benzene ring that is…
Q: 1. Name the following structures: CH3 CH3 b. CH - CH - a. CH,-CH CH CH3 - CH3 CH2 CH; CH3 CH3 CH CH2…
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Q: SOlve the attached
A: The reagents used in the above reaction are shown below.
Q: OC-C (chain) O C=N OC=C (aromatic) C-H (alkenyl or aryl) Oc-c O OH O C-H (alkyl) C=0
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Q: CH3-C C-CH3 CI ČH2-CH3 2-chloro-3-ethyl-2-buteno -
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Q: a) 2-chloro-2-methylbutane + CH,COOH b) isobutyl bromide + NaOMe c) 1-iodo-1-methylcyclohexane +…
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Q: Give the IUPAC name for each alkyne. CH;CH,CH(CH,)C=CCH,CH3 b. (CH,),CHC=CCH(CH3)2 С.…
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- Organotin compounds play a significant role in diverse industrial applications. They have been used as plastic stabilizers and as pesticides or fungicides. One method used to prepare simple tetraalkylstannanes is the controlled direct reaction of liquid tin(IV) chloride with highly reactive trialkylaluminum compounds, such as liquid triethylaluminum (Al(CzHs)3). 3SnCl4 + 4Al(C2H5)3 → 3Sn(C2H5)4 + 4AlCl3 In one experiment, 0.160 L of SnCl4 (d= 2.226 g/mL) was treated with 0.346 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)? If 0.257L of tetraethylstannane (d= 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?Choose the best reagents from the list provided below for carrying out the following conversion. Match the reagent with the step number. HCl (aq), Zn(Hg) KMnO4, H3O+ CH3Cl, AlCl3 HNO3, H2SO4 Cl2, FeCl3 fuming sulfuric acidArrange the alkyl halides in order of increasing reactivity in an SN2 reaction with KI in acetone (least first). I, IV, III, II II, III, I, IV IV, I, III, II III, II, IV, I
- give the reagents for parts a-pWhat is the organic chemistry mechanisms to get to this final product? one reagant is NaOCH2CH3Choose the best reagents from the list provided below for carrying out the following conversion. Match the reagent with the step number. HCl (aq), Zn(Hg) Br2, FeBr3 Na/NH3, -33 degrees C NBS, light KMnO4, H3O+ Mg metal, ether KOH, EtOH, heat
- Organotin compounds play a significant role in diverse industrial applications. They have been used as plastic stabilizers and as pesticides or fungicides.One method used to prepare simple tetraalkylstannanes is the controlled direct reaction of liquid tin(IV) chloride with highly reactive trialkylaluminum compounds, such as liquid triethylaluminum (Al(C2H5)3). 3SnCl4 + 4Al(C2H5)3 3Sn(C2H5)4 + 4AlCl3 In one experiment, 0.230 L of SnCl4 (d = 2.226 g/mL) was treated with 0.396 L of triethylaluminum (Al(C2H5)3); d = 0.835 g/mL). If 0.335 L of tetraethylstannane (d = 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?1. What type of reaction is occuring in step 3? (halogenation, hydrohalogenation, reduction, keto–enol tautomerism, dehydrohalogenation, acid-catalyzed hydration, base-catalyzed hydration) 2. Which reagent is necessary for step 3? (Br2, HBr, H2/Pt, NaNH2, H20/H2SO4/HgSO4)Organotin compounds play a significant role in diverse industrial applications. They have been used as plastic stabilizers and as pesticides or fungicides. One method used to prepare simple tetraalkylstannanes is the controlled direct reaction of liquid tin(IV) chloride with highly reactive trialkylaluminum compounds, such as liquid triethylaluminum (Al(C2H5)3). 3SnCl4 + 4AI(C2H5)3 →3Sn(C2H5)4 + 4AlCl3 In one experiment, 0.160 L of SnCl4 (d = 2.226 g/mL) was treated with 0.346 L of triethylaluminum (Al(C2H5)3): d = 0.835 g/mL). What is the theoretical yield in this experiment (mass of tetraethylstannane, Sn(C2H5)4)? If 0.257 L of tetraethylstannane (d= 1.187 g/mL) were actually isolated in this experiment, what was the percent yield?
- A mixture of 0.10 mol benzene and 0.10 mol p-xylene was allowed to react with 0.10 mol nitronium ion until all the nitronium ion was gone. Two products were obtained: 0.002 mol of one and 0.098 mol of the other. a. What was the major product? b. Why was more of one product obtained than of the other?1. Using Br2 in C2H4Br2 will result in HBr and ______. a. C2H3Cl3 b. C2H4Cl3 c. C2H2Cl3 d. none of the above 2. How many halogenation are posible in propane? a. 3 b. 8 c. 6 d. 10 3.Sulfonation of pentane will result in ________ and water. a. C5H11SO3H b. C5H12SO3H c. C5H14SO3H d. none of the above 4.Nitration of hexane will result in ________ and water. a. C6H13SO3H b. C6H15NO2 c. C6H13NO2 d. C6H14NO2 5.How many moles of O2 in heating a C12H26 (dodecane) a. 27 b. 37 c. 24 d. none of the aboveRank the species below in order of increasing nucleophilicity in protic solvent. I. H2O II. CH3S— III. CH3COO— IV. t-BuO— I, II, IV, III I, III, II, IV I, III, IV, II I, II, III, IV