H₂C CH3 CH₂ Br₂ CH₂C₂ Br- H₂C CH3 CH3 Br Electrophilic addition of bromine, Br, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism.

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter19: Aldehydes And Ketones: Nucleophilic Addition Reactions
Section19.SE: Something Extra
Problem 28VC
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196.

Subject : - Chemistry 

H₂C
CH3
H3C
CH3
CH3
:Br:
Br:
Br₂
CH₂Cl₂2
Br-
H3C
Br
Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a
bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂.
CH3
In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric
clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
27
[Review Topica
CH3
H3C
CH3
CH3
Br
[References)
CH3
Transcribed Image Text:H₂C CH3 H3C CH3 CH3 :Br: Br: Br₂ CH₂Cl₂2 Br- H3C Br Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 27 [Review Topica CH3 H3C CH3 CH3 Br [References) CH3
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