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please assign the chemical shift values in the given stucture show the splitting pattern plz i will upvote plzz
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- Reduction of an alkyl azide results in the formation of —-. A. an imine B. an oxime C. a tertiary amine D. a secondary amine E. a primary amineShow how the synthetic scheme developed in Problem 23.67 can be modified to synthesize this triiodobenzoic acid X-ray contrast agent.Possible alternative brominations include: Veratrole (1,2-dimethoxybenzene) to 1,2-dibromo-4,5-dimethoxybenzene; 4-Methylacetanilide to 2-bromo-4-methylacetanilide; 2-Methylacetanilide (made in experiment S.1) to 4-bromo-2-methylacetanilide; Vanillin to 5-bromovanillin; Acetanilide to 4-bromoacetanilide; a. b. C. d. e. EXPERIMENT S4: BROMINATION OF AROMATIC COMPOUNDS Certain other acetanilides made in experiment S.1 may also be used as precursors in this experiment. Estimated time: 1 afternoon Associated learning goals: Section 6, LG 6.6; Section 7, LG 7.2 and 7.4 Pre-lab report: complete the standard report form, and answer the following questions. In this experiment, molecular bromine (Br2) is generated from the redox reaction of potassium bromate with hydrobromic acid. Write a balanced equation for this process. Briefly outline the mechanism by which Br2 brominates your aromatic compound. Why do the bromine atoms end up at the positions indicated rather than anywhere else in the…
- Draw the possible stereoisomers of 2-methylocta-4,6-dien-1-amine. Note that E-, Z- isomers of each stereoisomer are also possible and would not be accounted for by the formula above; draw any E- or Z- isomers.Mustard gas, Cl¬CH2CH2¬S¬CH2CH2¬Cl, was used as a poisonous chemical agentin World War I. Mustard gas is much more toxic than a typical primary alkyl chloride. Itstoxicity stems from its ability to alkylate amino groups on important metabolic enzymes,rendering the enzymes inactive.(a) Propose a mechanism to explain why mustard gas is an exceptionally potent alkylatingagentDraw the structure of the following compounds: (1) (2S,4S)-2-ethyl-4-hydroxycyclopentan-1-one (2) (3E)-N,N-dimethyl-5-oxohex-3-enamide Please answer both
- what is the product(s) of the reaction of p-bromoaniline with HNO2, H2SO4, then CuCl and HClDraw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C = O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i. Part (b), then CH3COCl, AlCl j. CH3CHO, NaBH3CNWhen N-bromosuccinimide is added to hex-1-ene in CCl4 and a sunlamp is shone on themixture, three products result. Propose a mechanism that accounts for the formation of these three products
- Predict the products formed when cyclohexanone reacts with the following reagents.(a) CH3NH2, HGiven the following compounds and boiling points: Determine the IMFs Order the compounds from weakest to strongest IMFs, and Pentane (C5H12) 36°C Methane (CH4) -164°C Sodium n-butoxide (C4H9NaO) +260°C Hydrogen dioxide (H2O) 100°C3 Would the product be a(n) a) carbinolamine b) hydrazone c) imine d) hydrazine e) aminal