he figure below shows three edge views of a square loop with sides of length ℓ = 0.450 m in a magnetic field of magnitude 2.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field. Three figures show an x y coordinate plane with the +x-axis pointing to the right and the +y-axis pointing upward. A magnetic field labeled vector B points to the right in the positive x-direction. In each figure, a bar of length ℓ is shown in different orientations. In the first figure, the bar is oriented vertically, perpendicular to the magnetic field. In the second figure, the bar is tilted so that the top end is further right than the bottom end, making a 60.0° angle with the magnetic field. In the third figure, the bar is oriented horizontally, parallel to the magnetic field. (a) perpendicular to the magnetic field Wb (b) 60.0° from the magnetic field Wb (c) parallel to the magnetic field Wb hint The magnetic flux is ΦB = BA cos(θ) where θ is the angle between the magnetic field and the loop normal.
he figure below shows three edge views of a square loop with sides of length ℓ = 0.450 m in a magnetic field of magnitude 2.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field. Three figures show an x y coordinate plane with the +x-axis pointing to the right and the +y-axis pointing upward. A magnetic field labeled vector B points to the right in the positive x-direction. In each figure, a bar of length ℓ is shown in different orientations. In the first figure, the bar is oriented vertically, perpendicular to the magnetic field. In the second figure, the bar is tilted so that the top end is further right than the bottom end, making a 60.0° angle with the magnetic field. In the third figure, the bar is oriented horizontally, parallel to the magnetic field. (a) perpendicular to the magnetic field Wb (b) 60.0° from the magnetic field Wb (c) parallel to the magnetic field Wb hint The magnetic flux is ΦB = BA cos(θ) where θ is the angle between the magnetic field and the loop normal.
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter1: Introduction: The Nature Of Science And Physics
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Problem 22PE: What is the area of a circle 3.102 cm in diameter?
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The figure below shows three edge views of a square loop with sides of length ℓ = 0.450 m in a magnetic field of magnitude 2.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field.
Three figures show an x y coordinate plane with the +x-axis pointing to the right and the +y-axis pointing upward. A magnetic field labeled vector B points to the right in the positive x-direction. In each figure, a bar of length ℓ is shown in different orientations.
- In the first figure, the bar is oriented vertically, perpendicular to the magnetic field.
- In the second figure, the bar is tilted so that the top end is further right than the bottom end, making a 60.0° angle with the magnetic field.
- In the third figure, the bar is oriented horizontally, parallel to the magnetic field.
(a)
perpendicular to the magnetic field
Wb
(b)
60.0° from the magnetic field
Wb
(c)
parallel to the magnetic field
Wb
hint
The magnetic flux is
ΦB = BA cos(θ)
where θ is the angle between the magnetic field and the loop normal.
Transcribed Image Text:60.0°
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