he manufacturer of the X-15 steel-belted redial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. Crosset Truck Company bought a sample of 48 tires and found that the mean mileage for its trucks is 59,000 miles (i.e. less than the manufacturer’s claim) with a standard deviation of 5,000 miles.Test the manufacturer’s claim at a significance level (α) equals 5%.Would your answer in (1) change if significance level become 10%? Would your answer in (1) change if the probability of type I error equals zero? Justify your answerIf the same sample results had been obtained from a random sample of 125 tires, could your decision about the manufacturer’s claim changed using α=0.01 and comment on the results.Based on the sample size in (4), construct a 95% confidence level for the mean of mileage and comment on the results.dear, the last 2 questions are still pending regards

Name: he manufacturer of the X-15 steel-belted redial truck tire claims that
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Description: he manufacturer of the X-15 steel-belted redial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. Crosset Truck Company bought a sample of 48 tires and found that the mean mileage for its truck

One sample t-test: The one -sample t -test is used to determine whether the mean of sample differs…

Answered: he manufacturer of the X-15…

MATLAB: An Introduction with Applications

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ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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he manufacturer of the X-15 steel-belted redial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. Crosset Truck Company bought a sample of 48 tires and found that the mean mileage for its trucks is 59,000 miles (i.e. less than the manufacturer’s claim) with a standard deviation of 5,000 miles.

Test the manufacturer’s claim at a significance level (α) equals 5%.
Would your answer in (1) change if significance level become 10%?
Would your answer in (1) change if the probability of type I error equals zero? Justify your answer
If the same sample results had been obtained from a random sample of 125 tires, could your decision about the manufacturer’s claim changed using α=0.01 and comment on the results.
Based on the sample size in (4), construct a 95% confidence level for the mean of mileage and comment on the results.

dear, the last 2 questions are still pending

regards

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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