he method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do lin_arr1 = [10, 20, 30, 40, None]
he method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do lin_arr1 = [10, 20, 30, 40, None]
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter10: Pointers
Section10.3: Pointer Arithmetic
Problem 4E
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#using python
# the method take another circular array and returns a linear array containing the common elements between the two circular arrays.
def intersection(self, c2):
# To Do
lin_arr1 = [10, 20, 30, 40, None]
print("==========Test 10==========")
lin_arr9 = [10, 20, 30, 40, 50, None, None, None]
c10 = CircularArray(lin_arr9, 5, 5)
c10.printFullLinear() # This should print: 40, 50, None, None, None, 10, 20, 30
lin_arr10 = [5, 40, 15, 25, 10, 20, 5, None, None, None, None, None]
c11 = CircularArray(lin_arr10, 8, 7)
c11.printFullLinear() # This should print: 10, 20, 5, None, None, None, None, None, 5, 40, 15, 25
output = c10.intersection(c11)
print(output) # This should print: [10, 20, 40]
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