Health Care Public Option: A poll was conducted in 2009 in order to evaluate support for the healht care public option plan. 74% of 826 Democrats and 41% of 763 Independents support the public option. a) Calculate a 95% confidence interval for the difference between (Pp - Pi) and interpret it in this context. Assume all the conditions are met. Round your answers to the nearest percent. The confidence interval is: ( 0.025 %, 1.96 %) Interpret the confidence
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- What is meant by the sample space of an experiment?A research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (b) Given the method used by the environmental science teacher to collect the responses, explain how bias might have been introduced and describe how the bias might affect the point estimate of the proportion of all students at the school who would respond yes to the question.
- An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (a) How many students were in the sample selected by the environmental science teacher?An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (c) The statistics teacher at the high school was concerned about the potential bias in the survey. To obtain a potentially less biased estimate of the proportion, the statistics teacher used an alternate method for collecting student responses. A random sample of 300 students was selected, and each student was given the following instructions on how to respond to the question. • In private, flip a fair coin. • If heads, you…The International Nanny Association (INA) reports that in a sample of 928 in- home child care providers (nannies), 128 have passed the INA Nanny Credential Exam (2014 International Nanny Association Salary and Benefits Survey). A. Use Wilson’s adjustment to find a 95% confidence interval for the true proportion of all nannies who have passed the INA certification exam. B. We want to decide whether the proportion of who passed the INA certification exam exceeds than .12 answer both a and b.
- A poll asked adults in a certain country whether immigration was a good thing or a bad thing for the country. Out of 1032 respondents, 549 said it was a good thing. a. What percentage of those taking the poll said immigration was a good thing? b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. c. Find a 95% confidence interval for the proportion who believe immigration is a good thing.A poll asked adults in a certain country whether immigration was a good thing or a bad thing for the country. Out of 1066respondents, 670 said it was a good thing. a. What percentage of those taking the poll said immigration was a good thing? b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. c. Find a 95% confidence interval for the proportion who believe immigration is a good thing.1. A recent (June 11,2018) Gallup poll found that 48% of Americans identify as pro-choice on the issue of abortion. 1024 adults were polled. Calculate the margin of error. Using the margin or error from part a, what is the 95% confidence interval? If Gallop wanted a margin of error of 1%, how many people would they need to survey?
- A telephone service representative believes that the proportion of customers completely satisfied with their local telephone service is different between the South and the Midwest. The representative's belief is based on the results of a survey. The survey included a random sample of 11601160 southern residents and 12601260 midwestern residents. 43%43% of the southern residents and 56%56% of the midwestern residents reported that they were completely satisfied with their local telephone service. Find the 80%80% confidence interval for the difference in two proportions. Step 2 of 3 : Find the value of the standard error. Round your answer to three decimal placesDrinking A national health organization, concerned about drinking in middle school students, surveyed 220 randomly selected US 8th-grade students and found that 18 of them had had a drink of alcohol in the past month.(a) Find and interpret a 95% confidence interval for the proportion p of US 8th-grade students who drink alcohol.(b) Give the best estimate for p and give the margin of error for the estimate.A telephone service representative believes that the proportion of customers completely satisfied with their local telephone service is different between the South and the Midwest. The representative's belief is based on the results of a survey. The survey included a random sample of 11601160 southern residents and 12601260 midwestern residents. 43%43% of the southern residents and 56%56% of the midwestern residents reported that they were completely satisfied with their local telephone service. Find the 80%80% confidence interval for the difference in two proportions. Step 3 of 3 : Construct the 80%80% confidence interval. Round your answers to three decimal places.