Question

helen plays basketball. for free throws, she makes the shot 78% of the time. Helen must now attempt 2 free throws. C= the event that helen makes the first shot. P(C)=0.78. D=the event helen makes the 2nd shot. P(D)=0.78. the probability that helen makes the 2nd free throw given that she made the 1st is 0.86. what is the probability that helen makes both free throws?

Step 1

Consider C and D be the events Helen makes the first and the second shot respec...

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