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- Each box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?Please answer all parts of the following question about genes: PLEASE MAKE A PUNNETT SQUARE 1. For the following cross: Aa Bb cc Dd x Aa Bb CC Dd what is the chance of obtaining an individual who: a) shows all dominant traits? b) shows all recessive traits? c) is phenotypically like the second parent? d) is genotypically like the second parent? e) is heterozygous for all alleles? PLEASE MAKE A PUNNETT SQUAREFinish these crosses below:(assume all parents are homozygous for alleles) Cross 1:These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?
- Finish these crosses below:(assume all parents are homozygous for alleles) Cross 1: These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be? Cross 2: These are the parents: Vestigial Wings, Wild Type Body Male; Wild Type Wings and Ebony Body Female What are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be? Cross 3: These are the parents: Wild Type Male; White Eye Female What are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios.…1. A cow is heterozygous for three genes (WwPp) where W-White, w-Brown, P-Polled, p-Horned. Give the phenotypic and genotypic ratio of their offspring if the cow is inter se mated. 2.A male Sahiwal (RRHH) is crossed with a female Angus (Rrhh). Where R-Red, r-Brown, H-Horned, h-polled. Give the phenotypic and genotypic ratio of their offspring.BbRrppMm X bbRrPpMM: probability of producing an individual that is dominant for B & M and recessive for R and P?
- Punnet square problems A=Codominant; B=Codominant; O=Recessive Mary is homozygous for type A blood. Steve is homozygous for type O blood. If they have children, what are the possible phenotypes and genotypes of their children, and what is the probability of each? Mary and Steve have a son, Brad. Brad’s wife, Samantha is heterozygous for type B blood. If they have children, what are the possible phenotypes and genotypes of their children, and what is the probability of each? Stella loves roses and decides to cross her red rose with her white rose. All of the resulting offspring of this cross are pink roses. What can you say about the red and white alleles as a result of this cross? Stella decides to cross two of the pink roses. What are the possible genotypes and phenotypes of the offspring and the probabilities of each? DNA replication, Transcription and Translation problems It is S phase of the cell cycle, and time to replicate the cell’s DNA. Using the following strand of DNA…The allele for hitchhiker’s thumb (h) is recessive to straight thumb (H). If a man and his wife are both homozygous recessive, will any of their offspring potentially have hitchhikers thumb? 1.What genotype(s) must the offspring have in order to have the phenotypic trait of hitchhiker’s thumb? 2. Do a cross to determine all potential hitchhiker’s thumb genotypes and phenotypes for the offspring of this man and woman. Is it possible for any offspring of the F1 generation to have hitchhiker’s thumb?Suppose two parents, a father with the genotype AaBbccDd and a mother with the genotype aaBbCcDd, want to have children. Assume the loci are inherited independently of each other. Enter your answers as the most simplified fractions (e.g. 1/8 instead of 2/16). What proportion of the offspring are expected to have: The same genotype as the father? The same phenotype as the father? All dominant phenotypes? All recessive phenotypes?
- Finish these crosses below:(assume all parents are homozygous for alleles) Cross 3:These are the parents: Wild Type Male; White Eye FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?Doing genetic analysis it is determined that two parents are heterozygous for two separate unlinked recessive traits (i.e., both parents are heterozygous for both loci). Given this genetic information, what is the probability of their having a child which is homozygous recessive for both traits?What is the correct table in these two given? 1. Take two coins and assume that heads represent the dominantallele (A) and tails represents the recessive allele (a). The genotype for each coin isheterozygous (Aa).2. Assume that each coin represents one parent. When a single coin is flipped, one gameteis formed (through the process of meiosis). If the flipped coin is on heads, then thegamete has the dominant allele (A). When both coins are flipped simultaneously, therewill be two possible gametes that can combine through fertilization to form a zygote. Eachtime you flip both coins, you will record the “genotype” of the offspring.3. Flip the coins 100 times and record your results in the chart below
