Help please 3a and 3b if possible
2n5 co 2n5 Σ (-1) n° n2 3 n 5 nl 2+- п 1 n1 п п 5 12+ п -Σ 1 1 n1 + п 5 2+ п 1 1 +-+ п" п (by series comparison test =converges
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