Historians are interested in the accuracy of eyewitness accounts of traumatic events. One study examined survivors' recall of the sinking of the ship Titanic. The researchers reviewed the transcriprs of survirors testimony at governmental hearings, to see whether they testified that the ship was intact or breaking apart during the ships final plunge (it was in fact breaking apart). To test for likelihood of survivors saying the sip was intact or breaking apart.  Conlcusion :

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
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Problem 49E
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Historians are interested in the accuracy of eyewitness accounts of traumatic events. One study examined survivors' recall of the sinking of the ship Titanic. The researchers reviewed the transcriprs of survirors testimony at governmental hearings, to see whether they testified that the ship was intact or breaking apart during the ships final plunge (it was in fact breaking apart). To test for likelihood of survivors saying the sip was intact or breaking apart. 

Conlcusion :

Based on your descision, identify and explain the type of error you could be making with respect to the conclusions of the study; 

Data
Analyses
Edit
Exploration
T-Tests
ANOVA
Regression
Frequencies
Factor
Modules
Sa testimony
1
breaking apart
2
intact
3 breaking apart
breaking apart
5
breaking apart
intact
7
breaking apart
8 breaking apart
intact
10 breaking apart
11 breaking apart
12
intact
13 breaking apart
14 breaking apart
15 breaking apart
16 breaking apart
17 breaking apart
18
intact
19 breaking apart
20 breaking apart
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
Ready Y
Filters 0
Row count 20
Filtered 0
Deleted 0
Added 0
Cells edited 0
HOH
HOH
II
T
LO
Transcribed Image Text:Data Analyses Edit Exploration T-Tests ANOVA Regression Frequencies Factor Modules Sa testimony 1 breaking apart 2 intact 3 breaking apart breaking apart 5 breaking apart intact 7 breaking apart 8 breaking apart intact 10 breaking apart 11 breaking apart 12 intact 13 breaking apart 14 breaking apart 15 breaking apart 16 breaking apart 17 breaking apart 18 intact 19 breaking apart 20 breaking apart 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 Ready Y Filters 0 Row count 20 Filtered 0 Deleted 0 Added 0 Cells edited 0 HOH HOH II T LO
Expert Solution
Step 1

Null and alternative hypotheses:

The investigator is interested to test whether there was an equal likelihood of survivors saying the ship was intact or breaking apart.

Each of the survivors saying the ship was intact or breaking apart is equally likely to occur.

Denote the proportion of responses of intact as p1.

Denote the proportion of responses of breaking point as p2.

The hypotheses to be tested are:

Null hypothesis:

H0: p1 = p2

That is, there is an equal likelihood of survivors saying the ship was intact or breaking apart.

Alternative hypothesis:

Ha: p1p2

That is, there is no equal likelihood of survivors saying the ship was intact or breaking apart.

Test for the assumptions:

The necessary assumptions are given below:

  • The data should be the simple random values from both the populations.
  • The variable of interest must be categorical.
  • The samples should be independent.
  • The number of successes and failures in each sample must be greater than or equal to 5. That is, n1p1 ≥ 5, n1(1 – p1) ≥ 5, n2p2 ≥ 5, n2(1 – p2) ≥ 5.

Here, the sample of responses of breakdown and the sample of responses of intact are independent of each other.

Here, the variable of interest is “Response of the survivor” is categorical and testimony of 20 survivors was selected randomly.

It is given that among a sample of 20 survivors, 15 said breaking apart.

The sample size is n1 = 20.

The number of specified characteristics is x1 = 15.

It is given that among a sample of 20 survivors, 5 said intact.

The sample size is n2 = 20.

The number of specified characteristics is x2 = 5.

n1p1 = x1 = 15 and n1(1 – p1) = n1x1 = 5

n2p2 = x2 = 5 and n2(1 – p2) = n2x2 = 15

The number of successes and failures in each sample are not less than 5.

Thus, all the conditions to run the test are satisfied.

Step 2

Obtain the pooled estimate of proportion:

The sample proportion-1 is p1^ = 15/20 = 0.75.

The sample proportion-2 is p2^ = 5/20 = 0.25.

The pooled estimate of proportion is obtained as 0.9372 from the calculation given below:

Statistics homework question answer, step 2, image 1

Obtain the test statistic value:

Here, (p1p2) = 0, p1^ = 0.75, p2^ = 0.25, n1 = 20, n2 = 20.

The test statistic value is obtained as 3.16 from the calculation given below:

Statistics homework question answer, step 2, image 2

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