Hitchhiker's thumb is an autosomal recessive trait determined by a single gene with two alleles, H and h. Suppose the allele frequencies in a population are f(H) = 0.8 and f(h) = 0.2. %3D %3D Which combination(s) of genotype frequencies is/are possible in this population if it is in Hardy- Weinberg equilibrium? List all that are possible. O f(HH) = 0.64, f(Hh) = 0.32, f(hh) = 0.04 O f(HH) = 0.6, f(Hh) = 0.2, f(hh) = 0.2 f(HH) = 0.6, f(Hh) = 0.4, f(hh) = 0 O f(HH) = 0.7, f(Hh) = 0.2, f(hh) = 0.1 O f(HH) = 0.8, f(Hh) = 0, f(hh) = 0.2

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter19: Population Genetics And Human Evolution
Section: Chapter Questions
Problem 2QP: How Can We Measure Allele Frequencies in Populations? The MN blood group is a single-gene,...
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Hitchhiker's thumb is an autosomal recessive trait determined by a single gene with two alleles, H
and h. Suppose the allele frequencies in a population are f(H) = 0.8 and f(h) = 0.2.
Which combination(s) of genotype frequencies is/are possible in this population if it is in Hardy-
Weinberg equilibrium? List all that are possible.
O f(HH) = 0.64, f(Hh) = 0.32, f(hh) = 0.04
O f(HH) = 0.6, f(Hh) = 0.2, f(hh) = 0.2
%3D
f(HH) = 0.6, f(Hh) = 0.4, f(hh) = 0
%3D
f(HH) = 0.7, f(Hh) = 0.2, f(hh) = 0.1
O f(HH) = 0.8, f(Hh) = 0, f(hh) = 0.2
Transcribed Image Text:Hitchhiker's thumb is an autosomal recessive trait determined by a single gene with two alleles, H and h. Suppose the allele frequencies in a population are f(H) = 0.8 and f(h) = 0.2. Which combination(s) of genotype frequencies is/are possible in this population if it is in Hardy- Weinberg equilibrium? List all that are possible. O f(HH) = 0.64, f(Hh) = 0.32, f(hh) = 0.04 O f(HH) = 0.6, f(Hh) = 0.2, f(hh) = 0.2 %3D f(HH) = 0.6, f(Hh) = 0.4, f(hh) = 0 %3D f(HH) = 0.7, f(Hh) = 0.2, f(hh) = 0.1 O f(HH) = 0.8, f(Hh) = 0, f(hh) = 0.2
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