Host A sends a UDP datagram containing 8880 bytes of user data to host B over an Ethernet LAN. Ethernet frames may carry data up to 1500 bytes (i.e. MTU = 1500 bytes). Size of UDP header is 8 bytes and size of IP header is 20 bytes. There is no option field in IP header. How may total number of IP fragments will be transmitted and what will be the contents of offset field in the last fragment

Host A sends a UDP datagram containing 8880 bytes of user data to host B over an Ethernet LAN. Ethernet frames may carry data up to 1500 bytes (i.e. MTU = 1500 bytes). Size of UDP header is 8 bytes and size of IP header is 20 bytes. There is no option field in IP header. How may total number of IP fragments will be transmitted and what will be the contents of offset field in the last fragment

Comptia A+ Core 1 Exam: Guide To Computing Infrastructure (mindtap Course List)

10th Edition

ISBN:9780357108376

Author:Jean Andrews, Joy Dark, Jill West

Publisher:Jean Andrews, Joy Dark, Jill West

Chapter8: Network Infrastructure And Troubleshooting

Section: Chapter Questions

Problem 8TC

See similar textbooks

Similar questions

Supposed the scenario bellow, we have 3 networks to be submitted with the ip address 192.171.0.0/16. Network 1 has 150 host, network 2 has 100 and network 3 has 7 host. VLSM Decompose the given ip address to these networks using VLSM, and write the ip adress and the subnet mask for router 1, switch 0 , switch 2 , switch 3 , PC0 , PC1 , PC2
Computer Science Suppose We Are Going To Import A Capture Dump File Via WIRESHARK(Networking Analysis) Version 3.6.0 Show all steps on how to solve the following problems: A) Explore specific packet number let's suppose number 4 and give its source IP and MAC addresses (Show How To Do It With Steps - ScreenShots) B) Identify the Application protocols used in the communication (Show How To Do It With Steps - ScreenShots) C) Filter all TCP traffic and identify the login name and password (Show How To Do It With Steps - ScreenShots)
In ICT infrastructure, which of the following statements is true about the use of User Datagram Protocol (UDP) in Voice over Internet Protocol (VoIP)? VoIP often uses UDP because it offers low latency and is better suited for real-time communication than TCP. VoIP can use both TCP and UDP interchangeably, depending on the type of communication and the devices involved. UDP is used in VoIP only when the network has low congestion, otherwise TCP is used to ensure data reliability. VoIP always uses TCP to ensure that voice data is transmitted reliably. UDP is not used in VoIP because it does not support real-time communication.
For the given IP address 193.105.1.60/27, find the network address, First Address, Last address for the host, Broadcast address and next subnet address. please tery to anser in differnt way coz i dont same this answers to avoid plag try to do it in diffrent way with same answers Step 1 Given IP address 193.105.1.60/27 is a Class C address with CIDR /27 /27 means that the subnet mask is 255.255.255.224 Default subnet mask of Class C is /24 or 255.255.255.0 Here the CIDR is /27, so 3 bit subnetting is used, ie, 3- bit is borrowed from host part to network part. Number of hosts/subnetnetwork = 2m - 2, where m is the remaining bits in the host part, here m=5 =25 - 2=30 hosts Given IP 193.105.1.60/27 is in the network range 193.105.1.32 - 193.105.1.63 Step 2 Network address: It is the first address in the network range. So, 193.105.1.32 is the network address First Host address: It is the first valid host IP address which is…
so given two printer, one of IP address is 200.23.16.202 and subnet mask is 255.255.255.224, and other one IP address is 200.23.16.170 and subnet mask is 255.255.255.224. Suppose the network that hosts the above printer is re-configured with other networks in the building. After re-configuration, the printer's IP address would remain the same but its network is changed with a new subnet mask, which is changed to 255.255.255.128. This means, even the printer's IP address looks the same, its network ID and host ID are different from those before re-configuration. Find the new network ID and host ID of this printer. You must write both in the standard dot-decimal format without attaching the subnet mask.
A large number of consecutive IP addresses are available starting at 198.16.0.0. Sup- pose that four organizations, A, B, C, and D, request 4000, 2000, 4000, and 8000 ad- dresses, respectively, and in that order. For each of these, give the first IP address as- signed, the last IP address assigned, and the mask in the w.x.y.z/s notation. A router has just received the following new IP addresses: 57.6.96.0/21, 57.6.104.0/21, 57.6.112.0/21, and 57.6.120.0/21. If all of them use the same outgoing line, can they be aggregated? If so, to what? If not, why not? The set of IP addresses from 29.18.0.0 to 19.18.128.255 has been aggregated to 29.18.0.0/17. However, there is a gap of 1024 unassigned addresses from 29.18.60.0 to 29.18.63.255 that are now suddenly assigned to a host using a different outgoing line. Is it now necessary to split up the aggregate address into its constituent blocks, add the new block to the table, and then see if any reaggregation is possible? If not, what can be…
Consider the following topology. iMac2 wants to send a file to iMac3. iMac2 knows the destination IP of iMac3. Assuming that the fully configured network has just been switched on, explain the exact process that occurs to send the file from source to destination (only one way). Since many things happen along the way, you only need to address the following in your answer: 1. The appropriate names of the PDU during different stages 2. The ARP table population 3. The MAC table population 4. The usage and role of the IP Routing table (assume that the router already knows all routes to different networks) Hint: This question does not require explanation of the OSI Reference Model or TCP/IP stack. Your answer should be strictly structured in a step-by-step number-point format.
Suppose you have the following network requirements, for Given an IP address and mask of 9.0.0.0/8, design an IP addressing scheme using VLSM? How is the efficiency of this method achieved? Use the topology in Figure to answer the questions. a. Network 1 needs to support 330 host addresses. b. Network 2 needs to support 62 host addresses. c. Network 3 needs to support 2 host addresses. d. Network 4 needs to support 520 host addresses. e. Network 5 needs to support 230 host addresses. f. Network 6 needs to support 62 host addresses. g. Network 7 needs to support 2 host addresses. h. Network 8 needs to support 2 host addresses.
Consider the LAN below consisting of 12 computers (A-L) connected by two Ethernet bridges. At t=0 the bridging table entries for both bridges are empty. At t = 1, node L sends to node E, and node E replies immediately (well before the next time step). What are the (MAC address, interface) entries in the bridging tables right after these transmissions? Note: interface = port number a) Left-hand-side bridge: (L,15), (E, 8). Right-hand-side bridge: (L,7), (E, 5). b) Left-hand-side bridge: (L,8), (E, 8). Right-hand-side bridge: (L,7), (E, 7). c) Left-hand-side bridge: (L,15), (E,5). Right-hand-side bridge: (L,7), (E, 8). d) Left-hand-side bridge: (L,8), (E,8). Right-hand-side bridge: (L,7), (E, 7).
We explore whether either UDP or TCP offers any level of end-point authentication in this problem. a. Consider a server that accepts a request via UDP and responds via UDP (for example, as done by a DNS server). Where would the server give its answer if a client with IP address X spoofs it with address Y? b. Assume a server receives a SYN with IP source address Y and responds with SYNACK. The server then receives an ACK with IP source address Y and the right acknowledgmentamount. Assuming the server selects a random initial sequence number and there is no "man-in-the-middle," how can the server be confident that the recipient is really at Y (and not at any other address X that spoofs Y)?
Consider the following non-default subnet masks: (a) 255.255.248.0, (b) 255.128.0.0 . To which IP address class do they pertain?Write down the following in CIDR notation: (a) IP: 150.160.170.180, Subnet Mask:255.255.224.0; (b) IP: 75.80.85.90, Subnet Mask: 255.252.0.0 Three stations A, B, C and D are connected to a common Ethernet hub. Their IPaddresses and subnet mask are respectively: 200.100.50.67, 255.255.255.252;200.100.50.7, 255.255.255.248; 200.100.50.138, 255.255.255.240 and 200.100.50.1,255.255.255.254. Determine which among these stations can communicate with eachother. You need to show all detailed workings.
Each question is a judgment question. Write down your answer with T for True, F for False, and give the explanation if the answer is False. Consider a system of bandwidth 10Mbps, with multiple users, each is active (i.e., have data to transmit at rate 1Mbps) with a low probability, e.g. 0.1. From the capacity perspective, packet switching is better than circuit switching because the former can support more users. Denial of Service (DoS) attack can be generated by a large number of (legitimate) TCP connection requests to the same targeted server at the same time. These TCP requests can be originated from different hosts in a botnet, which is controlled by the attacker. In VSAT systems the micro-stations do not have sufficient power to communicate directly with one another; hence, they use a ground station called a hub with a high gain antenna to relay traffic. In the current Internet, communication across the Atlantic Ocean between the USA and Europe is mostly done by wireless…