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How do write an equation of a line that is perpendicular to -3x+4y=12 and having the same x-intercept?

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Given a line equation -3x+4y=12. We need to write it in terms of slope intercept form y=mx+b, where m is slope and b is y intercept.After writing in slope intercept form we get y = (3/4)x+3Slope = m = 3/4

The product of slope of two perpendicular lines is -1. Let us assume slope of perpendicular line be m1.So m1*(3/4)=-1. Using this equation we solve for m1&nbsp;as shown below.Slope m1=-(4/3)

The x intercept of line -3x+4y=12 is a point where y =0. Substituting y...

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How do write an equation of a line that is perpendicular to -3x+4y=12 and having the same x-intercept?

How do write an equation of a line that is perpendicular to -3x+4y=12 and having the same x-intercept?

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