How do write an equation of a line that is perpendicular to -3x+4y=12 and having the same x-intercept?
How do write an equation of a line that is perpendicular to -3x+4y=12 and having the same x-intercept?
Given a line equation -3x+4y=12. We need to write it in terms of slope intercept form y=mx+b, where m is slope and b is y intercept.
After writing in slope intercept form we get y = (3/4)x+3
Slope = m = 3/4
The product of slope of two perpendicular lines is -1. Let us assume slope of perpendicular line be m1.
So m1*(3/4)=-1. Using this equation we solve for m1 as shown below.
Slope m1=-(4/3)
The x intercept of line -3x+4y=12 is a point where y =0. Substituting y...
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