Asked Feb 10, 2019

How do write an equation of a line that is perpendicular to -3x+4y=12 and having the same x-intercept?

check_circleExpert Solution
Step 1

Given a line equation -3x+4y=12. We need to write it in terms of slope intercept form y=mx+b, where m is slope and b is y intercept.

After writing in slope intercept form we get y = (3/4)x+3

Slope = m = 3/4

Step 2

The product of slope of two perpendicular lines is -1. Let us assume slope of perpendicular line be m1.

So m1*(3/4)=-1. Using this equation we solve for mas shown below.

Slope m1=-(4/3)

Step 3

The x intercept of line -3x+4y=12 is a point where y =0. Substituting y...


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