How many Cals are required to heat a 28.4 g ice cube from -23.0 °C to -1.0 °C.

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How many Cals are required to heat a 28.4 g ice cube from -23.0 °C to -1.0 °C.

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Step 1

The specific heat capacity for a given substance can be defined  as the amount of heat that is needed to raise the temperature of a given substance per unit of the mass. The mathematical relationship between specific heat capacity, mass, change in temperature and the heat of the solution is given by the following equation:

Step 2

In this problem, it has been given that the mass of the ice is given to be 28.4 g.

The change in temperature is given to be from -23oC to -1oC which can be calculated as follows:

Step 3

The specific heat capacity of ice is 2.03 J/g oC.

Substituting al...

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