2. When 789 g of liquid ammonia is cooled from 82.7°C to 25.0°C it loses 214 kJ of heat. What is the specific heat capacity for liquid ammonia? A. 0.13 C. 0.0047 В. 4.19 Е. 4.70 D. 2.06
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- Formula: C3H6OMelting Point: -94.0°CBoiling Point: 56.0°CDensity of liquid: 0.791 g/mLHeat of Fusion: 98.14 J/gHeat of vaporization: 538.9 J/gSpecific heat capacity (solid): 1.653 J/g°CSpecific heat capacity (liquid): 2.161 J/g°CSpecific heat capacity (gas): 1.291 J/g°C How much heat is involved in taking 165.2 g of acetone from 14.7°C to 52.1°C?How much energy is removed when 433 g of steam (MW = 18.02 g/mol) is cooled to 70.0 °C? ΔHfusion = 6.01 kJ/mol, heat capacity = 75.3 J/(mol °C), and ΔHVAP = 40.6 kJ/mol.Formula: C3H6OMelting Point: -94.0°CBoiling Point: 56.0°CDensity of liquid: 0.791 g/mLHeat of Fusion: 98.14 J/gHeat of vaporization: 538.9 J/gSpecific heat capacity (solid): 1.653 J/g°C Specific heat capacity (liquid): 2.161 J/g°C Specific heat capacity (gas): 1.291 J/g°C A 523.70 g sample of acetone gas has a temperature of 56.0°C. How much heat is involved in converting it to a solid that has a temperature of -94.0°C? (Answer in Joules)
- Formula: C3H6OMelting Point: -94.0°CBoiling Point: 56.0°CDensity of liquid: 0.791 g/mLHeat of Fusion: 98.14 J/gHeat of vaporization: 538.9 J/gSpecific heat capacity (solid): 1.653 J/g°C Specific heat capacity (liquid): 2.161 J/g°C Specific heat capacity (gas): 1.291 J/g°C A 791.0 g sample of acetone sitting in the lab has a temperature of 21.7°C. How much heat would be involved in lowering the temperature of the acetone to -200.0°C? (answer in Joules)What mass of water (sweat) is required to cool a body weighing 74.1 kg from an initail temperature of 39.7˚C. to normal body temperature (37.4˚C)? Specific heat capacity of human body is 4.00 J/gC and the enthalpy of evaporation is 44.01 kJ/mol and the molar mass of water (sweat) is 18.016 g/mol.How much heat (kJ) is required to convert 3.12 moles of liquid benzene at 75.1°C to gaseous benzene at 115.1°C? The following information may be useful.b.p = 80.1CCm (liquid benzene) = 136.0 J/ (mol * °C)ΔHvap = 30.72 kJ/molCm (gaseous benzene) = 36.6 J/ (mol * °C)
- 1 kg of benzene is poured into a flask and heated to 353 K (the boiling point of benzeneat 1 atm.) using a heating element that has a power of 700 W (we ignore thatit's probably not so healthy and smart to do). After 5 minutes, when the benzene has stoodboiling point, the heating element is taken up, and the remaining mass of benzene in the flaskmeasured at 470 grams. Determine the enthalpy of vaporization of benzene.a sample of 98g of pure sulfuric acid is dissolved in 2.0 kg of water in an insulated vessel at 15°C, and thetemperature rises rapidly because of the process of forming the solution. The reaction is summarized in theequation H2SO4(l) -> H+(aq) + HSO4 –(aq). Estimate the temperature change assuming that the heat capacityof the solution is 4.0 J/gK and the heat capacity of the vessel is 300 J/K.The scenario: You have two cups of water at temperatures Th and Tc (in Celcius), each of which contains the same mass, m (in kg) of water. When you put them in a freezer, a mass (m, in kg) immediately evaporates off the hot water. Ignore evaporation from the cold water. The specific heat of liquid water is c (in kJ/kg/C), the specific latent heat of vaporization of water is Lv (in kJ/kg), and the specific latent heat of fusion of water is Lf (in kJ/kg). Write a symbolic expression for QC, the amount of heat (in kJ) that must be removed from the cold water in order to lower its temperature to 0°C, and then freeze it. Your expression will involve the variables m, c, Tc, and Lf
- Estimate the thermal properties of a food with the following composition: carbohydrate 0.3%, protein 27.6%, fat 17.5%, ash 4.7%, moisture 49.9%. a. Specific heat is based on the Siebel equation = kJ / kg ° C. b. Specific heat is based on the Charm equation = kJ / kg ° C. c. Specific heat is based on the Heldman & Singh equation = kJ / kg ° C. d. Specific heat is based on the Choi & Okos equation = kJ / kg ° C. e. Heat conductivity is based on the equation Sweat = W / m ° C. f. Heat conductivity is based on the Choi & Okos equation = W / m ° C. g. Heat diffusivity based on the Choi & Okos equation = m² / s.The following information is given for antimony at 1 atm: Tb= 1440.00°C Hvsp=(1440.00°C) = 1.605*10^3 J/g Tm= 631.00°C H fus=(631.00°C) =161.1 J/g Specific heat solid = 0.2090 J/g °C Specific heat liquid = 0.2590 J/g °C A 21.10 g sample of solid antimony is initially at 609.00°C. If the sample is heated at constant pressure ( P= 1 atm), what kJ of heat is needed to raise the temperature of the sample to 729.00°C.A rigid vessel contains 0.014 m3 of saturated-vapor steam in equilibrium with 0.021 m3 of saturated-liquid water at 373.15 K (100°C). Heat is transferred to the vessel until one phase just disappears, and a single-phase remains. Which phase (liquid or vapor) remains, and what are its temperature and pressure? How much heat is transferred in the process?