How many grams of Al203 are formed from 15.0L of 02 at 97.3 kPa and 21 degrees C according to the following equation: 4AI + 302 2AI203

Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter13: Gases
Section: Chapter Questions
Problem 118AP: 2.50Lcontainer at 1.00atm and 48Cis filled with 5.41gof a monatomic gas. Determine the identity of...
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G criminologist
G biologist L counseling
O Job Opportunities..
O Workforce Resour.
* Work in Loudoun -.
E Summer & Part Ti..
E sources
L daddy day care
behind the u
Find the mistake. A student calculated their answer to a gas law problem as shown in the image below. Their answer is incorrect. Review their work
and find the mistake the student made in their calculation. The question is typed in the upper left corner.
Hint: There is only 1 step that is incorrect and the issue IS NOT related to significant figures!
Click here for the Gas Laws Formula Sheet.
Click here for the Periodic Table.
6:V:15.0LD2たスく+る7ろこスタサK,
P=97.3 ePa , R=8.314 L·kla
い-n Cmoe)
E:PV=n RT→ n=PV
How many grams of
Al203 are formed
from 15.0L of 02 at
97.3 kPa and 21
mol. K
degrees C according
to the following
equation:
4AI + 302 → 2AI203
Sn=37.3 kDa (5.0Kう RT
8う4Kefa
Given L.
start with
Ideal Gas
Law.
S n-0.597mol O2
0597mol2 molA203 1203.92gAl203 =81.169
2 3 mot02
Al203
B
MacBook Air
Transcribed Image Text:G criminologist G biologist L counseling O Job Opportunities.. O Workforce Resour. * Work in Loudoun -. E Summer & Part Ti.. E sources L daddy day care behind the u Find the mistake. A student calculated their answer to a gas law problem as shown in the image below. Their answer is incorrect. Review their work and find the mistake the student made in their calculation. The question is typed in the upper left corner. Hint: There is only 1 step that is incorrect and the issue IS NOT related to significant figures! Click here for the Gas Laws Formula Sheet. Click here for the Periodic Table. 6:V:15.0LD2たスく+る7ろこスタサK, P=97.3 ePa , R=8.314 L·kla い-n Cmoe) E:PV=n RT→ n=PV How many grams of Al203 are formed from 15.0L of 02 at 97.3 kPa and 21 mol. K degrees C according to the following equation: 4AI + 302 → 2AI203 Sn=37.3 kDa (5.0Kう RT 8う4Kefa Given L. start with Ideal Gas Law. S n-0.597mol O2 0597mol2 molA203 1203.92gAl203 =81.169 2 3 mot02 Al203 B MacBook Air
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