   Chapter 13, Problem 118AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
27 views

# 2 . 5 0 − L container at 1 .00 atm and − 48 ° C is filled with 5 . 41 g of a monatomic gas. Determine the identity of the gas. Assuming the 2 . 5 0 − L container is a large elastic balloon, predict what will happen when 1 0.0  g of oxygen gas is added to the balloon (which already contains 5 . 41 g of the monatomic gas).ovide values for each of the following variables. In addition, explain what is happening for each variable, incorporating the kinetic molecular theory into your explanation.m>Temperature of gas mixture = ?Km>Total moles of gas mixture = ?molm>Total pressure of gas mixture = ?atmm>Volume of balloon = ?L Now assuming the 2 . 5 0 − L container is rigid (like a steel container), predict what will happen when 1 0.0  g of oxygen gas is added to the container (which again already contains 5 . 41 g of the monatomic gas).ovide values for each of the following variables. In addition, explain what is happening for each variable, incorporating the kinetic molecular theory into your explanation.m>Temperature of gas mixture = ?Km>Total moles of gas mixture = ?molm>Total pressure of gas mixture = ?atmm>Volume of rigid container = ? L

Interpretation Introduction

(a)

Interpretation:

To determine the identity of the gas based on the pressure, volume and temperature given.

Concept Introduction:

The ideal gas equation is:

PV=nRT

Where,

P = Pressure of the gas

V = Volume of the gas

n = moles of the gas

R = Universal gas constant

T = Temperature of the gas.

Explanation

The ideal gas equation is

PV=nRT

Where,

P = Pressure of the gas = 1.00 atm

V = Volume of the gas = 2.50 L

n = moles of the gas = ?

R = Universal gas constant = 0.0821 L.atm/mol.K

T = Temperature of the gas = -48 ° C = 225 K

Substituting the values in the given equation, we get,

PV=nRT1.00atm×2.50L=n×0.0821L.atm/mol.K×225Kn=0.135mol

Thus, the moles of the gas = 0

Interpretation Introduction

(b)

Interpretation:

To determine the values of different variables when another gas is added to the elastic balloon which already has a monatomic gas in it.

Concept Introduction:

The ideal gas equation is:

PV=nRT

Where,

P = Pressure of the gas

V = Volume of the gas

n = moles of the gas

R = Universal gas constant

T = Temperature of the gas.

Interpretation Introduction

(c)

Interpretation:

To determine the values of different variables when another gas is added to the rigid steel container this already has a monatomic gas in it.

Concept Introduction:

The ideal gas equation is:

PV=nRT

Where,

P = Pressure of the gas

V = Volume of the gas

n = moles of the gas

R = Universal gas constant

T = Temperature of the gas.

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