How many grams of aluminum chloride will be produced from the complete reaction of 43.5 grams of aluminum nitrate with excess sodium chloride in the following reaction: Al(NO3)3 + 3NaCl ⟶ AlCl3 + 3NaNO3

General, Organic, and Biological Chemistry
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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.71EP: How many moles of beryllium (Be) are needed to completely react with 10.0 moles of N2 in the...
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How many grams of aluminum chloride will be produced from the complete reaction of 43.5 grams of aluminum nitrate with excess sodium chloride in the following reaction:

Al(NO3)3 + 3NaCl ⟶ AlCl3 + 3NaNO

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