How many grams of Cl2 can be prepared from the reaction of 16.0g of MnO2 and 30.0g of HCl according to the following balanced chemical equation? MnO2 + 4HCl --> MnCl2 + Cl2 + 2H2O

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How many grams of Cl2 can be prepared from the reaction of 16.0g of MnO2 and 30.0g of HCl according to the following balanced chemical equation? MnO2 + 4HCl --> MnCl2 + Cl2 + 2H2O

I figured that MnO2 would be irrelevant because it doesn't have Cl in it. Is this assumption incorrect?

11. How many grams of Cl2 can be prepared from the reaction of 16.0 g of MnO2 and 30.0 g of HCl according
to the following balanced chemical equation?
MnO2 + 4HCI → MnCl2 + Cl2 + 2H2O
Hel, A. 6.52
B. 7.29 g 30.0, HC mols HC)
C13.0 g-
fereme D 14.6 g
mols clz 70.9
14.69 Clz
36.458, HCI 4mols HC) mols Cl2
E 58 4 g
Transcribed Image Text:11. How many grams of Cl2 can be prepared from the reaction of 16.0 g of MnO2 and 30.0 g of HCl according to the following balanced chemical equation? MnO2 + 4HCI → MnCl2 + Cl2 + 2H2O Hel, A. 6.52 B. 7.29 g 30.0, HC mols HC) C13.0 g- fereme D 14.6 g mols clz 70.9 14.69 Clz 36.458, HCI 4mols HC) mols Cl2 E 58 4 g
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