The reaction between methanol (CH3OH), and hydrobromic acid (HBr) forms bromoethane (CH3Br) and water (H₂0). Our reaction recipe calls for 1.3 molar equivalents of hydrobromic acid for every mole of methanol. a. What is the stoichiometric ratio of hydrobromic acid and bromoethane for the reaction as it occurs? b. If you run the reaction with 2.5 moles of methanol, how many moles of hydrobromic acid does our recipe call for? How many moles of hydrobromic acid would actually be used in the reaction?

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The reaction between methanol (CH³OH), and hydrobromic acid (HBr) forms bromoethane (CH³Br) and water (H₂0).
Our reaction recipe calls for 1.3 molar equivalents of hydrobromic acid for every mole of methanol.
a. What is the stoichiometric ratio of hydrobromic acid and bromoethane for the reaction as it occurs?
b. If you run the reaction with 2.5 moles of methanol, how many moles of hydrobromic acid does our recipe call
for? How many moles of hydrobromic acid would actually be used in the reaction?
Transcribed Image Text:The reaction between methanol (CH³OH), and hydrobromic acid (HBr) forms bromoethane (CH³Br) and water (H₂0). Our reaction recipe calls for 1.3 molar equivalents of hydrobromic acid for every mole of methanol. a. What is the stoichiometric ratio of hydrobromic acid and bromoethane for the reaction as it occurs? b. If you run the reaction with 2.5 moles of methanol, how many moles of hydrobromic acid does our recipe call for? How many moles of hydrobromic acid would actually be used in the reaction?
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