Q: 1. What is the percent by volume of a solution formed by mixing 15 mL of isopropanol with 55 mL of…
A: Percent by volume = (volume of solute/volume of solution) x 100% Volume of solution = volume of…
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A: Magnesium chloride dissociate as ., MgCl2 ⇌ Mg2+ + 2Cl-
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A: Given data: Volume of ethyl acetate = 25 mL Volume of solution = 150mL Formula used: %(v/v)=Volume…
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A:
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A: Given: Initial concentration of glucose solution = 35 % Concentration after dilution of glucose…
Q: grams
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A: Number of moles off methanol = 2.701g / 32.04 g/mol = 0.084mole mass of water = density * volume…
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A: Volume percent or percentage by volume v/v is one of the concentration terms that indicates the…
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A: Number of moles of solute present in 1 liter of solution is known as molarity of the solution.
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A: Given : % w/v of KCl solution = 40 % And volume of solution = 10 mL
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A: solution=solute +solvent Example :ethanol +water Ethanol=solute Water=solution Percent solution…
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A: Welcome to bartleby! Introduction : We have to calculate mass of oil .
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A: Given :- % (w/v) aqueous glucose solution = 5.16% Volume of solution = 150.0 mL To calculate :-…
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A: The ppm also known as parts per million is a term used to measure the concentration of the solutions…
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A:
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A: Definition: Molarity is a concentration term for a solution. The molarity of a given solution is…
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A: The volume of the solute(ethanol)= 50 mL The volume of the solvent(water0=180 mL Therefore, the…
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A: The carbonic acid has molecular formula H2CO3 and it has two hydrogen atoms. The provided…
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A: Given information: Concentration of HCl = 15 M New concentration of HCl = 3 M New volume of HCl…
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A: Since the moles of H2SO4 in final 100 mL of 0.10 M solution is coming from only 6.0 M H2SO4 solution…
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A:
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A: volume percent is defined as volume of solute to the ratio of volume of solution.
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A: The mass of solute in grams present in 100 mL of solution is known as the mass percent concentration…
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A: The molarity of required solution is calculated using equation of dilution.
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A: Percentage mass by volume defined as the ratio of weight of solute in grams to the volume of…
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A: The given data contains, mass = 50 mg = 0.05 g. Molarity = 0.25 M
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A: Mass of the solution is calculated as shown in equation (1) where ρ and V are the density and volume…
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A: The mass of solute in gram present in 100 g solution is known as the mass percent concentration of a…
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A: Since you have posted multiple questions, we are entitled to answer the first only.
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A: Given :- Concentration of solution = 30% Volume of solution = 240 mL To calculate :- Amount of…
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A: 5% aqueous solution of 1,6 Hexanediamine that means 100 mL of solution contain 5 gm of solute 1,6…
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A: Welcome to bartleby! Introduction : We have to calculate mass percentage .
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A:
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A:
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A: Given, 250mL of a 0.3M
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A:
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A: Using formula of molarity moles of solute can be calculated. Given : Molarity = 0.350M and.…
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A: Given :- Mass of NaCl = 50.0 g Mass of water = 150.0 g To calculate :- Mass percent of solution…
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- Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray contrast agent that aids with the radiologic imaging of the anatomy. One such contrast agent is sodium diatrizoate, a nonvolatile water-soluble compound. A 0.378-m solution is prepared by dissolving 38.4 g sodium diatrizoate (NaDTZ) in.l.60 102 mL water at 3 1.2C (the density of water at 31.2C is 0.995 g/cm3). What is the molar mass of sodium diatrizoate? What is the vapor pressure of this solution if the vapor pressure of pure water at 31.2C is 34.1 torr?A solution is prepared by dissolving 40.00 g of MgCl2 (f.w. = 95.211 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 2 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Determine the freezing point of the solution.A solution is prepared by dissolving 40.00 g of MgCl2 (f.w. = 95.211 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 2 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Determine the osmotic pressure in atm.
- how many grams of barium carbonate BaCO3 are dissolved in: a) 1 liter of clean water b) 1 liter of solution 0,1 N Ba (NO3) 2 c) 300 ml of 0.01N BaCl2 solution during the calculations take into account that Ksp of BaCO3 = 4 × 10-⁹Although other solvents are available, dichloromethane(CH₂Cl₂) is still often used to “decaffeinate” drinks because thesolubility of caffeine in CH₂Cl₂ is 8.35 times that in water.(a) A 100.0-mL sample of cola containing 10.0 mg of caffeine is extracted with 60.0 mL of CH₂Cl₂. What mass of caffeine re-mains in the aqueous phase? (b) A second identical cola sampleis extracted with two successive 30.0-mL portions of CH₂Cl₂.What mass of caffeine remains in the aqueous phase after each extraction? (c) Which approach extracts more caffeine?The partial molar volumes of acetone and chloroform, in a solution in which the molar fraction of chloroform is 0.4693, are 74.166 cm3mol-1 and 80.235 cm3 mol-1, respectively. What is the volume of 1,000 kg of this solution? Data: M.M. (acetone) = 58.08 gmol-1; M.M. (chloroform) = 119.07 gmol-1.
- Ben prepared a salicylic acid in pentanol solution by adding 4.77 g of salicylic acid to 91.88 mL of pentanol. Calculate the mole fraction of salicylic acid in this solution. MW of salicylic acid= 138.12 g/mol MW of pentanol= 88.15 g/mol Density of pentanol= 0.8144 g/mLC7H21O4NHCl(aq) + NaOH(aq) ---> C17H21O4N(aq) + H2O (l) + NaCl(aq) When a 25mL of aqueous solution that contains 62.50g of the salt is treated with NaOH, the salt is converted to pure cocaine. How much water in litres is needed additionally to dissolve the formed pure cocaine?A solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Find the freezing point of the solution(in C to 2 decimal places)
- A solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Find the osmotic pressure in atm to three decimal placesA solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Determine the following: Boiling point of solution (in °C to two decimal places) Freezing point of solution (in °C to two decimal places) Vapor pressure of the solution (in atm to three decimal places) Osmotic pressure (in atm to three decimal places)1. Calculate the mass required to prepare a 250 mL 3 M NaCl in water.Mass = M x MM x V 10002. Calculate how to prepare the following dilutions, ½, ¼, 1/8 and 1/16 of the initial concentration.There is a helpful equation that is used to determine how much stock solution and how much diluent to combine to get the final solution of a desired concentration