How many milliliters of a stock solution of 5.80 M HNO3 would you have to use to prepare 0.130 L of 0.490 M HNO3? V= 11.0 mL  I need help with part b of the questions: If you dilute 10.0 mL of the stock solution to a final volume of 0.330 L , what will be the concentration of the diluted solution? M= __M

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