How many mL of (1.2000x10^-1) M nitric acid are needed to react completely with (3.35x10^1) mL of (1.5100x10^-1) M sodium carbonate? The balanced reaction is: 2 HNO3 + Na2CO3 – H2O + CO2 + 2 NANO3 Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer

How many mL of (1.2000x10^-1) M nitric acid are needed to react completely with (3.35x10^1) mL of (1.5100x10^-1) M sodium carbonate? The balanced reaction is: 2 HNO3 + Na2CO3 – H2O + CO2 + 2 NANO3 Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter2: Chemical Compounds

Section: Chapter Questions

Problem 143QRT: The present average concentration (mass percent) of magnesium ions in seawater is 0.13%. A chemistry...

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3.37 If atypical grain of sand occupies a volume of 1.3 × 10-4 cm3, what is the volume (in cm3) of 1 mole of sand (ignoring the space between grains)? What is the volume in liters?
The present average concentration (mass percent) of magnesium ions in seawater is 0.13%. A chemistry textbook estimates that if 1.00 × 108 tons Mg were taken out of the sea each year, it would take one million years for the Mg concentration to drop to 0.12%. Do sufficient calculations to either verify or refute this statement. Assume that Earth is a sphere with a diameter of 8000 mi, 67% of which is covered by oceans to a depth of 1 mi, and that no Mg is washed back into the oceans at any time.
A soft drink contains an unknown mass of citric acid, C3H5O(COOH)3. It requires 6.42 mL of 9.580 × 10−2-M NaOH to neutralize the citric acid in 10.0 mL of the soft drink. C3H5O(COOH)3(aq) + 3 NaOH(aq) → Na3C3H5O(COO)3(aq) + 3 H2O(ℓ) Determine which step in these calculations for the mass of citric acid in 1 mL soft drink is incorrect? Why? n (NaOH) = (6.42 mL)(1L/1000 mL)(9.580 × 10−2 mol/L) n (citric acid) = (6.15 × 10−4 mol NaOH) × (3 mol citric acid/1 mol NaOH) m (citric acid in sample) = (1.85 × 10−3 mol citric acid) × (192.12 g/mol citric acid) m (citric acid in 1 mL soft drink) = (0.354 g citric acid)/(10 mL soft drink) Determine the correct result.
How many grams of water must be used to prepare a 2.50 percent by mass (%m/m) sodium hydroxide (NaOH) solution from 12.7 g NaOH? Report your result in decimal notation and to the proper number of significant figures. All numbers are measured. a) 2.50 g water b) 5.08 g water c) 12.7 g water d) 495 g water e) 508 g water
The sugar content of a wine is determined five times, and the following results obtained: 150, 155, 155, 152 en 144 g/L. Determine with 90% confidence if the 5th value (144 g/L) must be excluded (outlier) or included (not outlier) in further calculations
I am trying to ascertain the density of 0.9-M HCl. The book provides a density of 1.0-M HCl as 1.016g/mL. I know the Molecular Weight aka Molar Mass is 36.46g/mol I also know that the equation to calculate the density in this instand is: Density=(Molarity x Molecular Weight)/WeightI have found examples online, and one answer provided here that shows the Density of 0.9-M HCl is 0.9115g/mL. That answer was arrived at as follows:Density = (0.9M x 36.46g/mol)/36 = 32.814/36 = 0.9115g/mL My problem is that I don't understand where the 36 came from for "weight", and I need to be able to show all unit measurements for each step. So my issue has 2 parts: 1) How was the Weight value determined to be 36 (I need to see the formula)2) Where in the step-by-step process is mL in there so that after all cancellations/conversions are completed, the only remaining units are g/mL to show how 0.9115g/mL was arrived at.
When pure magnesium chloride dissolved in water, its ions dissociate completely in water. a) Comment in the ability of that solution to conduct electricity. b) A student dissolved 1.78 g of magnesium chloride in 0.500 L of water to prepare a solution of concentration M. From that solution he took a volume of 0.05 L in another flask (S). Calculate the number of moles of magnesium chloride in the second flask (S). (show all your calculations, units and significant figures are important)
An alcoholic fermentation was conducted in the laboratory using 280 g glucose as substrate with a working volume of 2,000 mL. Assuming that the sugar is completely fermented to ethanol. Calculate the volume of ethyl alcohol in liters produced. The density of ethyl alcohol is 0.79 g/mL and its concentration or percent ethyl alcohol by volume produced assuming that no volume changed during fermentation.
(When answering this problem, report the answer with the appropriate number of significant figures. When entering units, use proper abbreviated units with proper capitalization.)A beverage drink mix sample is prepared by mixing a packet of beverage powder in a gallon (3.78 L) of water. A sample for analysis is prepared by diluting 10.00 mL of this solution in a 50.0 mL volumetric flask. A student calculates that the concentration of dye in the analyzed beverage mix solution is (2.59x10^-5) mol/L. Determine the mass (in grams) of food dye in the beverage mix packet. Hint: The answer is assumed to be reduced to the highest power possible.
From the moles of magnesium hydroxide (see attached), calculate the grams of magnesium hydroxide this corresponds to (the molar mass of magnesium hydroxide is 58.305 g/mol) and then convert this to milligrams. This is how many mg of Mg(OH)2 are in the initial mass of milk of magnesia that you used. From this ratio (mg of Mg(OH)2 in grams of milk of magnesia), calculate how many mg of Mg(OH)2 are in a standard 15 mL dose of the milk of magnesia. (The density of milk of magnesia is 1.06 g/mL, use that to convert "15 mL" to units of grams.)
Mass of Empty Beaker is 141.2g, Beaker + Water is 388.3g, mass of water is 247.1g, volume of water is 0.2471mL, calculate volume H2=Volume displaced water
As part of the aspirin synthesis lab the orgo students also had to perform the following calculation to demonstrate their knowledge. Are you able to help them work this out? Saponification is a process in which soap is produced from the chemical reaction between animal fat (triglycerides) and a strong base such as KOH. An example of such balanced chemical reaction is shown here: C51H98O6 + 3KOH → C3H5(OH)3 + 3C16H31O2K (Triglyceride) (Soap) if during the saponification reaction 231.5 g of C51H98O6 is mixed with 231.5 g of KOH and 160 g of soap is produced. Calculate the theoretical yield of soap C16H31O2K and indicate who is the limiting reactant. (Provide your answer to 2 decimal places) Calculate the percent yield for this reaction (Provide your answer to 1 decimal place) *Show ALL steps and mathematical equations involved in your calculations to help the orgo students. Remember to label all…