How many mL of a 0.525 M CaI2 is needed to reduce 18.0 mL of a 1.46 M KMnO4 solution:      10 I  ̶  +  2  MnO4  ̶  + 3 SO4  ̶   + 16 H+  →  5 I2  +  2 Mn+  +  3 SO4  ̶  +  8 H2O

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.20QE
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How many mL of a 0.525 M CaI2 is needed to reduce 18.0 mL of a 1.46 M KMnO4 solution:

    

10 I  ̶  +  2  MnO ̶  + 3 SO ̶   + 16 H+  →  5 I2  +  2 Mn+  +  3 SO ̶  +  8 H2O

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