How many mL water must be added to produce a. 625 mL of 1.00M solution from 6.00M solution? b. 2.5L of 0.250M solution from 0.450M solution?

Q: A 67.0 mL portion of a 1.70 M solution is diluted to a total volume of 228 mL. A 114 mL portion of…

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Q: What volume of a 0.159 M calcium hydroxide solution is required to neutralize 21.7 mL of a 0.121M…

A: Given, Molarity of perchloric acid solution =0.121 Mvolume of perchloric acid solution =21.7…

Q: 1. What is the weight (in grams) to prepare a 350 mL of 0.047 M solution? 2. What is the…

A: The mass of the compound can be calculated by the number of moles of compound and molar mass of the…

Q: A 64.0 mL aliquot of a 1.60 M solution is diluted to a total volume of 268 mL. A 134 mL portion of…

A: The number of moles of aliquot in the first solution is calculated using equation (1). In this…

Q: What volume in mL of 0.300 M NaF would be required to make a 0.0175 M solution of NaF when diluted…

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Q: A 776-mL sample of 0.229 M MgBr, solution is prepared in a large flask. A 76.1-mL portion of the…

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Q: What volume of a 0.314 M hydrobromic acid solution is required to neutralize 27.3 mL of a 0.161 M…

A: Molarity of hydrobromic acid = 0.314 M  Molarity of Calcium hydroxide solution = 0.161 M  Volume of…

Q: A 65.0 mL portion of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of…

A: When the solution is diluted then the concentration of the solution decreases.  So the concentration…

Q: A 74.0 mL portion of a 1.70 M solution is diluted to a total volume of 268 mL. A 134 mL portion of…

A: We can determine the dilution factor by using the given below formula :…

Q: You have a solution of 0.1609 M zinc(II) chloride. (a) How many moles of solute are contained in…

A: Given: Molarity of solution = 0.1609 M Volume of solution = 47.13 ml = 47.13 × 10-3 L

Q: A 65.0 mL65.0 mL portion of a 1.50 M1.50 M solution is diluted to a total volume of 228 mL.228 mL. A…

A: Molarity(M) is the moles of solute per unit volume of the solution in liters. It's unit is mol/L

Q: What volume of a 0.243 M hydrochloric acid solution is required to neutralize 20.7 mL of a 0.175 M…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: What volume in ml of 0.300 M NaF would be required to make a 0.0790 M solution of NaF when diluted…

A: We know that the number of moles of solute during the dilution is Constant The number of moles of…

Q: What is the number of milli equivalent. of AgNO3 are contained in 31.9 ml of 0.0922 N AgNO3 solution

A: Given, Volume of Solution = 31.9 mL Normality = 0.0922 N Number of miliequivalents = ?

Q: 15. You have 15 mL of a 0.25 M NaCl(aq) solution. What volume should you dilute it to in order to…

A: "To get remaining sub-parts solved please repost the complete question and mention the sub-parts to…

Q: What volume of a 4.00 × 10–4 M FeSCN2+ solution would be needed to prepare 40.0 mL of a 7.20 × 10–5…

A: Given Molarity (M1) = 4.00 × 10-4 M Volume ( V1 ) = ?  Molarity (M2) = 7.20× 10-5 M Volume ( V2) =…

Q: A 64.0 mL64.0 mL portion of a 1.40 M1.40 M solution is diluted to a total volume of 258 mL.258 mL. A…

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Q: What volume of 0.0589 M  calcium hydroxide is required to neutralize 28.60 mL of 0.0785 M  nitric…

A: Balanced chemical equation for the neutralization of calcium hydroxide with nitric acid: Ca(OH)2  +…

Q: What volume of 0.547 M sulfuric acid solution (in mL) is needed to neutralize 50.00 mL of 0.0812 M…

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Q: How many mL of 4.50 M calcium hydroxide solution would be required to completely react with 6.36 mL…

A: Given: Concentration of calcium hydroxide (Ca(OH)2) =4.5 M Concentration of hydrochloric acid…

Q: A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of…

A: Given :Initial concentration of solution = 1.20 M Initial volume of solution = 67.0 mL And final…

Q: A 53.0 mL53.0 mL portion of a 1.70 M1.70 M solution is diluted to a total volume of 248 mL.248 mL. A…

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Q: A 75.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 228 mL. A 114 mL portion of…

A: Record the given data, Initial volume = 75 mL Initial Molarity = M1 = 1.50 M Total volume = 228 mL…

Q: A 64.0 mL aliquot of a 1.80 M solution is diluted to a total volume of 228 mL. A 114 mL portion of…

A: Given:Initial volume = 64 mLInitial Molarity = M1 = 1.80 MTotal volume = 228 mLVolume of water added…

Q: 21. How many milliliters of a 0.500 M aluminum sufate solution will react with 15 0 mL of a 3.20 M…

A: Molarity (M) :-  The number of moles of solute dissolved in one litre of solution is known as…

Q: A 54.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 278 mL. A 139 mL portion of…

A: The answer to the following question can be written as:

Q: What mass of water (grams) must be added to 72.5 g KNO3 to generate 2.00 L of aqueous solution with…

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Q: How many milliliters of 0.15 M HCI must be added to 50.4 mL of 0.44 M HCI to give a final solution…

A: The solution is given below -

Q: What volume of a 0.109 M calcium hydroxide solution

A: The amount of substance in certain volume of solution is called as molarity. Molarity is a property…

Q: What volume of a 0.186 M perchloric acid solution is required to neutralize 26.1 mL of a 0.180 M…

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Q: What volume of a 0.142 M perchloric acid solution is required to neutralize 24.0 mL of a 0.182 M…

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Q: What volume of a 0.143 M barium hydroxide solution is required to neutralize 23.3 mL of a 0.134 M…

A: The expression of dilution law is shown below: M1V1 =M2V2 where; M1 = molarity of known solution V1…

Q: What volume of a 0.178 M potassium hydroxide solution is required to neutralize 27.1 mL of a 0.110 M…

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Q: A 74.0 mL74.0 mL aliquot of a 1.40 M1.40 M solution is diluted to a total volume of 238 mL.238 mL. A…

A: Given : Initial concentration of aliquot = 1.40 M  Initial volume of solution = 74.0 mL

Q: What volume (in mL) of a 0.250 M sodium sulfate solution is needed to precipitate all the barium, as…

A: The balanced equation for the given reaction is, Na2SO4 + Ba(NO3)2   ---> BaSO4 + 2NaNO3 Moles of…

Q: To prepare 500 mL of a 0.350 M HCl solution from a 12 M solution, you require

A: Initial concentration (M1) = 12 M  Initial volume (V1) = V ml  Final concentration (M2) = 0.350 M…

Q: What volume of 0.0117 M  calcium hydroxide is required to neutralize 71.50 mL of 0.0132 M  nitric…

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Q: What volume in mL of 0.300 M NaF would be required to make a 0.0145 M solution of NaF when diluted…

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Q: 23.6 mL of a 1.1 M solution of lithium hydroxide is used to prepare a solution with a concentration…

A: Molarity can be defined as the ratio of number of moles to that of volume of solution in liters.

Q: A solution with a total volume of 300 mL contains 37.85 g of NaCl. a. Determine the molarity of NaCl…

A: Given We know about the the molarity before adding other solution and after adding other solution…

Q: A 52.0 mL portion of a 1.80 M solution is diluted to a total volume of 248 mL. A 124 mL portion of…

A: Dilution of the solution: On dilution of the solution with the pure water, the mole of solute…

Q: 6.0 M KNO3 would be required to create 700.0 mL of a 0.75 M KNO3 solution?

A: Applying formula  M1V1 = M2V2  where M1 = 6.0M , V1=? ,              M2 = 0.75M , V2= 700.0mL

Q: What volume of a 0.1 m sodium hydroxide could be made with the 200 g of solute

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Q: A  57.0 mL  portion of a  1.60 M  solution is diluted to a total volume of  278 mL.  A  139 mL…

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Q: You have a 2.00 M solution of sucrose and need to use it make 1.0 L a 0.500 M solution of sucrose.…

A: The volume of sucrose needed to be taken is determined by considering the formula M1V1 = M2V2.

Q: If 30. g of AgNO3 is available, what volume of 0.10 M AgNO3 solution can be prepared? Volume =…

A: Molarity is the concentration unit .It is defined as moles of solute in Liter of solution . It is…

Q: A 57.0 mL aliquot of a 1.30 M solution is diluted to a total volume of 208 mL. A 104 mL portion of…

A: Dilution Factor: “It is the ratio of total volume to volume of solute” or “It is the ratio of…

Q: What volume of a 0.108 M potassium hydroxide solution is required to neutralize 17.8 mL of a 0.265 M…

A: Given, For potassium hydroxide, M1= 0.108 M V1=? For hydrochloric acid, M2= 0.265 M V2 = 17.8 mL

Q: if you have a 261 mL of a 3.12 M solution what concentration will you have after adding 376 mL of…

A: Given is, V1= 261 mL N1= 3.12 M Volume of water = 376 mL N2=??

Q: What volume of a 0.166 M hydrochloric acid solution is required to neutralıze 24.7 ml. of a 0.168 M…

A: For Ba(OH)2, n-factor = 2   Normality of Ba(OH)2 solution , N1  = molarity x n-factor…