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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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When a solution is diluted by adding additional solvent, the concentration of solute changes hut the amount of solute present does not change. Explain. Suppose 250. mL of water is added to 125 mL of 0.55 1 M NaCl solution. Explain how you would calculate the concentration of the solution after dilution.

Interpretation Introduction

Interpretation:

The explanation corresponding to fact that if a solution is diluted by additional solvent, then the concentration of solute changes but the amount of solute present does not change is to be stated. After dilution with 250mL of water, the concentration of the given 125mL solution of 0.551M

NaCl is to be calculated.

Concept Introduction:

Solution may be defined as the mixture of a minor component which is known as solute and the major component that is known as solvent. The solute is uniformly distributed in the solvent.

The solution is a liquid mixture that contains solute dissolved homogeneously in solvent. Solute is present in small amount as compared to solvent present in the solution.

Explanation

The molarity or concentration of the solution is defined as the total mole of the solute per unit volume of the solution. The expression for the same is,

Molarity=MolesVolumeL

According to this expression, concentration is inversely proportional to the volume of the solution. Thus, the addition of more solvent increases the volume of the solution and decreases the concentration of the solution but this addition does not have any effect on the moles of the solute. Therefore, the amount or mass of the solute present in the solution does not change. The moles of the solute remain the same throughout the solution.

The given initial volume, V1 of NaCl solution is 125mL.

The given final volume, V2 of NaCl solution after the addition of 100mL of water is 125mL+100mL=225mL.

The given initial concentration C1 of NaCl solution is 0.551M.

If the sample of the solution possesses two different conditions then, the expression is,

C1V1=C2V2

Where,

  • C1 is the initial concentration of the solution

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