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- The compound whose 1H NMR spectrum is shown has the molecular formula C3H6Br2. Propose a structure.What is the structure of the compound with the formula C8H10O, that shows six signals in its 13C-NMR spectrum, The 1H-NMR spectrum is: 1.98 ppm (1H singlet) 2.82 ppm (2H triplet) 3.80 ppm (2H triplet) 7.22 ppm (5H broad multiplet)The 1H-NMR spectrum of compound B,C7H14O , consists of the following signals: δ 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H). Draw the structural formula of compound B.
- identify the compound with molecular formula C2H6O that gives this 1H NMR spectrum.Identify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound A exhibits peaks at 1.75 (doublet, 3 H, J = 6.9 Hz) and 5.89 (quartet, 1 H, J = 6.9 Hz) ppm. Compound B exhibits peaks at 4.16 (singlet, 2 H), 5.42 (doublet, 1 H, J = 1.9 Hz), and 5.59 (doublet, 1 H, J = 1.9 Hz) ppm.Which of the following structures would have fewer 13C signals than 1H signals in its NMR spectra? a) 1 b) 2 c) 3 d) 4 e) 5
- Draw the structure of C3H8O and indicate which sets of hydrogens correspond to which signal in the H NMR spectrum.The 1H-NMR spectrum of 1-bromopropane shows signals at 1.03, 1.88, and 3.39 ppm. The 1H-NMR spectrum of 2-bromopropane shows signals at 1.73 and 4.21 ppm. Draw these two molecules and assign the correct chemical shift to each proton environment.What is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?