Question
Asked Dec 2, 2019
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How much energy needs to be added in the form of heat to turn a 50 kg block of ice at -20 deg C into steam at 135 deg C? 
Lf=333 kJ/kg
Lv=2256 kJ/kg Cice=2.108 kJ/KgdegC Cwater=4.187 kJ/kgdegC Csteam=1.996kJ/kgdegC

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Expert Answer

Step 1

Energy needed to change the temperature of ice from -20 deg C to 0 deg C is

Е 3 т,ДТ
1ce
10
/kg.C
(0°С - (-20°C))
2.108 KJx
= (50kg)
1kJ
103J
= (50kg 2.108 KJx
1kJ
kg.C
(20°C)
2108000J
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Е 3 т,ДТ 1ce 10 /kg.C (0°С - (-20°C)) 2.108 KJx = (50kg) 1kJ 103J = (50kg 2.108 KJx 1kJ kg.C (20°C) 2108000J

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Step 2

Energy needed to convert 50 kg of ice into water at 0 deg C is

EmL
103J
(50kg) 333 KJx
/kg
1kJ
16650000J
help_outline

Image Transcriptionclose

EmL 103J (50kg) 333 KJx /kg 1kJ 16650000J

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Step 3

Energy needed to change temperature of w...

Е, - тс в АТ
water
103J
/kg. °C(100°C-0°C)
1kJ
= (50kg) 4.187 KJ:
103
/kg. °C
1kJ
(100°C)
= (50kg 4.187 KJ x .
20935000 J
help_outline

Image Transcriptionclose

Е, - тс в АТ water 103J /kg. °C(100°C-0°C) 1kJ = (50kg) 4.187 KJ: 103 /kg. °C 1kJ (100°C) = (50kg 4.187 KJ x . 20935000 J

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