Asked Jan 20, 2019

How much heat energy, in kilojoules, is required to convert 59.0 g of ice at −18.0 ∘C to water at 25.0 ∘C ?


Expert Answer

Step 1

Specific heat of ice (Cp) = 2.10 J/g. oC

specific heat of water (Cp) = 4.18 J/g. oC

heat of fusion (dHfus) = 334 J/g

Step 1: ice at -18oC to ice at 0oC

q1 = mCpdT = (59.0 g) x (2.10 J/g. oC) x (0 + 18) = 2230.2 J

Step 2: convert ice to water at 0 oC

q2 = mdHfus = (59.0 g) x (334 J/g) = 19706 J

Step 3: water at 0 ...

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