Asked Dec 17, 2019

How much impulse is needed to stop a 10-kg bowling ball moving at 6m/s?


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He have Impulse momentum Eguation, F= (mv) dt d(mv) Fdt Fdt = m dv m( Vz-ui] I : mfo-6] I =(10)6) = - 60 Ag/s) I= 60 kg-


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Newtons Laws of Motion

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