How much work is done by friction on the block as it slides across the rough part?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 21P: A 5.00-kg block is set into motion up an inclined plane with an initial speed of i = 8.00 m/s (Fig....
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The photo includes all of the information, the questions I am having trouble on are: How much work is done by friction on the block as it slides across the rough part?
A 3.00-kg block starts from rest at the top of an incline at height yo = 2.50 m åboVe the
floor. It slides down the frictionless incline onto the floor, and then encounters a rough
part of the floor that has a coefficient of kinetic friction u = 0.500. It slides 2.00 m across
this surface before the floor is again frictionless. It then slides up another frictionless
incline on the other side. (There are four situations here, labeled "0" through “3".)
m = 3.0 kg
eirli isrli sto Sagota stoled obila oold erlt e9ob snibni 19rio aril d wold 5
(9g0 Hk 0.509ostaib orls Jo ingl orff et
2 W
2.5 m
2.0 m
1. What is the initial gravitational potential energy PE, of the block? (Use the floor as
the reference point where PE = 0.)
PE = 3K9x9.8m52x2.5m
PE 73.5 J
%3D
PEO=(mass of bloCK)X(accelerationdue to gravity).
hijght af block frem flçer)
2. What is the speed v, of the block just before it reaches the rough part of the flóor?
KE= 0
PEotEo = 73.5 J
conservation of energy
%3D
From
x3x Vq = 73.5
73.5
1.5
Transcribed Image Text:A 3.00-kg block starts from rest at the top of an incline at height yo = 2.50 m åboVe the floor. It slides down the frictionless incline onto the floor, and then encounters a rough part of the floor that has a coefficient of kinetic friction u = 0.500. It slides 2.00 m across this surface before the floor is again frictionless. It then slides up another frictionless incline on the other side. (There are four situations here, labeled "0" through “3".) m = 3.0 kg eirli isrli sto Sagota stoled obila oold erlt e9ob snibni 19rio aril d wold 5 (9g0 Hk 0.509ostaib orls Jo ingl orff et 2 W 2.5 m 2.0 m 1. What is the initial gravitational potential energy PE, of the block? (Use the floor as the reference point where PE = 0.) PE = 3K9x9.8m52x2.5m PE 73.5 J %3D PEO=(mass of bloCK)X(accelerationdue to gravity). hijght af block frem flçer) 2. What is the speed v, of the block just before it reaches the rough part of the flóor? KE= 0 PEotEo = 73.5 J conservation of energy %3D From x3x Vq = 73.5 73.5 1.5
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