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How strong is the data? Did it agree or disagree?

How strong is the data? Did it agree or disagree?

An Introduction to Physical Science
An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter3: Force And Motion
Section: Chapter Questions
Problem 15MC: Angular momentum is conserved in the absence of which of the following? (3.7) (a) inertia (b)...
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How strong is the data? Did it agree or disagree?
6:39 Data Table 3.3. Varying the Centripetal Force ..... Time needed Time needed to Centripetal Force mg (in N) Trial with to make 1 make 10 (in 1/sec') Hanging mass, (kg) Revolution Revolutions - Period, T (in sec) (in sec) 0.030 kg 0.294 N 19.28s 1.928s 0.2690 0.040 kg 0.392 N 15.35s 1.535s 0.4244 0.050 kg 0.49 N 13.59s 1.359s 0.5414 ------ -. 0.060 kg 0.588 N 12.73s 1.273s 0.6171 .... 0.070 kg 0.686 N 11.69s 1.169s 0.7318
Transcribed Image Text:6:39 Data Table 3.3. Varying the Centripetal Force ..... Time needed Time needed to Centripetal Force mg (in N) Trial with to make 1 make 10 (in 1/sec') Hanging mass, (kg) Revolution Revolutions - Period, T (in sec) (in sec) 0.030 kg 0.294 N 19.28s 1.928s 0.2690 0.040 kg 0.392 N 15.35s 1.535s 0.4244 0.050 kg 0.49 N 13.59s 1.359s 0.5414 ------ -. 0.060 kg 0.588 N 12.73s 1.273s 0.6171 .... 0.070 kg 0.686 N 11.69s 1.169s 0.7318
6:39 Table 3.4. Results (Varying the Centripetal Force). Mass of the Brass Object. = 0. 208 kg m, - 208.19g g to kg: g/1000 : 208.19/ 1000 : 0.20819 kg 0.208 kg Slope of the trendline (from the graph Fe vs.1T) slope, m(F, T') = 0.882 N m. [computed using the slope,m (F.T)) m, = 0. 22 N slope,m (FCT³) = 0.882 radius, r= 0.994 = 0.882N 4п2 (0.994) m. = 0.022 N
Transcribed Image Text:6:39 Table 3.4. Results (Varying the Centripetal Force). Mass of the Brass Object. = 0. 208 kg m, - 208.19g g to kg: g/1000 : 208.19/ 1000 : 0.20819 kg 0.208 kg Slope of the trendline (from the graph Fe vs.1T) slope, m(F, T') = 0.882 N m. [computed using the slope,m (F.T)) m, = 0. 22 N slope,m (FCT³) = 0.882 radius, r= 0.994 = 0.882N 4п2 (0.994) m. = 0.022 N
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