: How would you prepare a liter of "carbonate buffer" at a pH of 10.10? H2CO3 > H* + HCO3 Ka = 4.2 x 10-7 HCO3 > H* + co3 2 Ka = 4.8 x 10-11

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
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Chapter14: Principles Of Neutralization Titrations
Section: Chapter Questions
Problem 14.9QAP
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: How would you prepare a liter of "carbonate buffer" at a pH of 10.10?
H2CO3 > H* + HCO3
Ka = 4.2 x 10
HCO3 +> H* + co3 2
Ka = 4.8 x 10-11
13 buffer is preferred to prepare at mole ratio of 0.40 to 1.0, dissolve in enough water to make up a
1-L solution
2nobuffer is preferred to prepare at mole ratio of 0.60 to 1.0, dissolve in enough water to make up a
1-L solution
13 buffer preferred to prepare at mole ratio of 0.60 to 1.0, dissolve in enough water to make up a 1-
L solution
2nd buffer is preferred to prepare at mole ratio of 0.40 to 1.0, dissolve in enough water to make up
a 1-L solution
Transcribed Image Text:: How would you prepare a liter of "carbonate buffer" at a pH of 10.10? H2CO3 > H* + HCO3 Ka = 4.2 x 10 HCO3 +> H* + co3 2 Ka = 4.8 x 10-11 13 buffer is preferred to prepare at mole ratio of 0.40 to 1.0, dissolve in enough water to make up a 1-L solution 2nobuffer is preferred to prepare at mole ratio of 0.60 to 1.0, dissolve in enough water to make up a 1-L solution 13 buffer preferred to prepare at mole ratio of 0.60 to 1.0, dissolve in enough water to make up a 1- L solution 2nd buffer is preferred to prepare at mole ratio of 0.40 to 1.0, dissolve in enough water to make up a 1-L solution
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